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3 years ago

The sequence a, = 2, 4, 8, 16, 32, ... is the same as the sequence ay = 2,

Mathematics

1 answer:

blondinia [14]3 years ago

4 0

Answer:

TRUE

Step-by-step explanation:

TRUE

a_1 = 2

a_n = 2*(an_1)

if we start with 2, we would get

a_2 = 2*(a_1) = 2*(2) = 4

a_3 = 2*(a_2) = 2*(4) = 8

a_4 = 2*(a_3) = 2*(8) = 16

a_5 = 2*(a_4) = 2*(16) = 32

and so on

You might be interested in

If sine theta equals three over four, what are the values of cos θ and tan θ?

ratelena [41]

Answer:

In words, Cosine theta equals plus or minus square root of seven over 4,tangent theta equals plus or minus three over root seven

Step-by-step explanation:

Given that sin ∅ =3/4 It means the ratio of the opposite side to the hypotenuse side is 3:4.

Using the Pythagoras theorem we can calculate the hypotenuse adjacent as follows.

a²+b²=c²

a²=c²-b²

a²=4²-3²

a²=16-9

a²=7

a=√7

Then Cos ∅= opposite/ adjacent

=√7/4

Then Tan ∅ = opposite/adjacent

=3/√7

In words, Cosine theta equals plus or minus square root of seven over 4,tangent theta equals plus or minus three over root seven.

7 0

3 years ago

Brandon’s family went out to dinner. The dinner bill was $85 and the family gave the server a 20% tip. How much is the tip?

gregori [183]

Answer: The tip is $17

Step-by-step explanation: You multiply $85 by .2 to get this answer.

7 0

3 years ago

Read 2 more answers

Of a total of 100 buses operated within a particular town, 48 usually run on time and 36 of these buses are owned by Jerry. Of t

miv72 [106K]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

Below is similar question:

<span>48 out of 100 private buses usually run on time. Out of the buses that are on time, only 36 are owned by Jerry. Out of the remaining 52 buses that usually run late, only 7 are owned by Jerry. What is the probability that a bus is owned by Jerry, given that it runs on time?
A. 0.58
B. 0.67
C. 0.75
D. 0.81
</span>
The answer is C as <span>36/48 = .75</span>

4 0

3 years ago

Read 2 more answers

Calculus piecewise function.

Kipish [7]

Part A

The notation $\lim_{x \to 2^{+}}f(x)$ means that we're approaching x = 2 from the right hand side (aka positive side). This is known as a right hand limit.

So we could start at say x = 2.5 and get closer to 2 by getting to x = 2.4 then to x = 2.3 then 2.2, 2.1, 2.01, 2.001, etc

We don't actually arrive at x = 2 itself. We simply move closer and closer.

Since we're on the positive or right hand side of 2, this means we go with the rule involving x > 2

Therefore f(x) = (x/2) + 1

Plug in x = 2 to find that...

f(x) = (x/2) + 1

f(2) = (2/2) + 1

f(2) = 2

This shows $\lim_{x \to 2^{+}}f(x) = 2$

Then for the left hand limit $\lim_{x \to 2^{-}}f(x)$ , we'll involve x < 2 and we go for the first piece. So,

f(x) = 3-x

f(2) = 3-2

f(2) = 1

Therefore, $\lim_{x \to 2^{-}}f(x) = 1$

===============================================================

Part B

Because $\lim_{x \to 2^{+}}f(x) \ne \lim_{x \to 2^{-}}f(x)$ this means that the limit $\lim_{x \to 2}f(x)$ does not exist.

If you are a visual learner, check out the graph below of the piecewise function. Notice the gap or disconnect at x = 2. This can be thought of as two roads that are disconnected. There's no way for a car to go from one road to the other. Because of this disconnect, the limit doesn't exist at x = 2.

===============================================================

Part C

You'll follow the same type of steps shown in part A.

However, keep in mind that x = 4 is above x = 2, so we'll deal with x > 2 only.

So you'd only involve the second piece f(x) = (x/2) + 1

You should find that f(4) = 3, and that both left and right hand limits equal this value. The left and right hand limits approach the same y value. The limit does exist here. There are no gaps to worry about when x = 4.

===============================================================

Part D

As mentioned earlier, since $\lim_{x \to 4^{+}}f(x) = \lim_{x \to 4^{-}}f(x) = 3$ , this means the limit $\lim_{x \to 4}f(x)$ does exist and it's equal to 3.