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3 years ago

Step-by-step square root of 79

Mathematics

1 answer:

alex41 [277]3 years ago

4 0

Answer:

79 does not have a defined square root.

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Can someone plz help me on this plz I have the answer just making sure I’m right. Plz no link s

aalyn [17]

What’s the answer you have currently

3 0

3 years ago

Read 2 more answers

1 (15 Points]. Prove the following statement: is divisible by 3 if only if it is a sum of three consecutive integers. be ddvisbk

Alinara [238K]

Answer:

<em>First.</em> Let us prove that the sum of three consecutive integers is divisible by 3.

Three consecutive integers can be written as k, k+1, k+2. Then, if we denote their sum as n:

n = k+(k+1)+(k+2) = 3k+3 = 3(k+1).

So, n can be written as 3 times another integer, thus n is divisible by 3.

<em>Second. </em>Let us prove that any number divisible by 3 can be written as the sum of three consecutive integers.

Assume that n is divisible by 3. The above proof suggest that we write it as

n=3(k+1)=3k+3=k + k + k +1+2 = k + (k+1) + (k+2).

As k, k+1, k+2 are three consecutive integers, we have completed our goal.

Step-by-step explanation:

4 0

2 years ago

Simplify the product (x-4)(x+3)

Kamila [148]

Answer:

Final answer is $x^2-x-12$ .

Step-by-step explanation:

Given expression is $\left(x-4\right)\left(x+3\right)$ .

Now we need to find the product of the given expression $\left(x-4\right)\left(x+3\right)$ .

$\left(x-4\right)\left(x+3\right)$

$=x\left(x-4\right)+3\left(x-4\right)$

$=x^2-4x+3x-12$

combine like terms

$=x^2-1x-12$

$=x^2-x-12$

Hence final answer is $x^2-x-12$ .

7 0

3 years ago

Read 2 more answers

HELP ASAP!!!!! Given: Point B is on the perpendicular bisector of AC¯¯¯¯¯. BD¯¯¯¯¯ bisects AC¯¯¯¯¯ at point D. Prove: B is equid

Harlamova29_29 [7]

Answer: Missing parts are,

In first blank, $AD\cong DC$ ,

In second blank, SAS postulate

In third blank, CPCTC postulate

Step-by-step explanation:

Since, Here D is the mid point on the line segment AC.

And BD is a perpendicular to the line AC.

Therefore, In triangles ADB and CDB ( shown in figure)

AD\cong DC ( By the definition of mid point)

$\angle BDA\cong \angle BDC$ ( right angles )

$BD\cong BD$ ( reflexive)

Thus, By SAS ( side angle side )postulate,

$\triangle ADB\cong \triangle CDB$

So, by CPCTC( Corresponding parts of congruent triangles are congruent)

$AB\cong CB$

Now, By definition of congruent segment,

AB=CB

By definition of equidistant,

B is equally far from both A and C.

7 0

2 years ago

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Explain the converse of the Pythagorean theorem.

tangare [24]

The answer is b ......

6 0

3 years ago