The correct answer is A, if you use photomath you can usually find the answers to most algebra problems
A) 4a - 3b + 2c
4(2, -1, 5) - 3(4, 3 , -2) + 2(5, 4, 0) = (8, -4, 20) - (12, 9, - 6) + (10, 8, 0) =
= (8 - 12 + 10 , -4 - 9 + 8 , 20 + 6 + 0) = (6, - 5, 26)
Answer: (6, - 5, 26)
b) magnitude of vector b

c) vector of length 7 parallel to vector c
=> m(5,4,0) = (5m,4m,0)
=>

=> m = 7 / √41 ≈ 1.093
=> 1.093 (5, 4, 0) = (5.465 , 4.372, 0)
Answer: (5.465 , 4.372 , 0)
A pound of oranges cost x dollar => A pound of pears cost x+3 dollar
We have: 8x+4(x+3)=30 => 12x=30-12=18 =>x=1.5
5 pounds of pears cost: 5(x+3)=5(1.5+3)=5*4.5= 22.5 (dollar)
Answer:
b
Step-by-step explanation:
Volume is a three-dimensional scalar quantity. The volume of the space between the cylinder and the two cones is 1184.43183 cm³.
<h3>What is volume?</h3>
A volume is a scalar number that expresses the amount of three-dimensional space enclosed by a closed surface.
Given the circumference of the base is 61 cm, therefore, the radius of the base will be,
Circumference = 61 cm
2πR = 61
R = 61/(2π) = 9.70845 cm
The volume of the cylinder(Outside shell) can be written as,
Volume = πR²×H
= π× (9.70845)² ×12
= 3553.29326 cm³
The volume of the two identical cones will be,
The volume of the cone = 2× (1/3) × π × R² × H
= (2/3)×π×(9.70845²)×12
= 2368.86143 cm³
The volume of the space between the cylinder and the two cones is,
The volume between space = 3553.29326 cm³ - 2368.86143 cm³
= 1184.43183 cm³
Hence, the volume of the space between the cylinder and the two cones is 1184.43183 cm³.
Learn more about Volume:
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