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Shtirlitz [24]
3 years ago
10

A horizontal force of magnitude 356 N is employed to push a 78.0-kg block a distance of 18.6 m on a rough horizontal surface. If

the block moves at a constant speed, (a) What is the work done by the 356-N force? (b) What is the coefficient of kinetic friction between the block and the rough surface?
Physics
1 answer:
icang [17]3 years ago
5 0

Answer:

6621.6 Joule

0.46525

Explanation:

F = Force = 356 N

s = Displacement = 18.6 m

m = Mass of block = 78 kg

Work done

W=F\times s\\\Rightarrow W=356\times 18.6\\\Rightarrow W=6621.6\ J

The work done by the horizontal force is 6621.6 Joule

F=\mu mg\\\Rightarrow \mu=\frac{F}{mg}\\\Rightarrow \mu=\frac{356}{78\times 9.81}\\\Rightarrow \mu=0.46525

The coefficient of friction between the block and the rough surface is 0.46525

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Explanation:

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