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Lerok [7]
2 years ago
7

Water flowing through a garden hose of diameter 2.74cm fills a 25-L bucket in 1.50 min. (b) A nozzle is now attached to the end

of the hose. If the nozzle diameter is one-third the diameter of the hose, what is the speed of the water leaving the nozzle?
Physics
1 answer:
KiRa [710]2 years ago
7 0

The Speed of the water leaving the end of the nozzle = 4.25 m/s.

<h3>What is the speed of the water leaving the nozzle?</h3>

Discharge, Q = Av,

where A is the area discharging section and v is the velocity of flow.

Volume of bucket = 25.0 L

Time taken = 1.50 min

Discharge = Volume / Time

= 25/1.5

= 16.67 L/min.

Diameter of hose = 2.74 cm = 0.0274 m

Q = Av

$2.78 * 10^{-4} = (\pi * 0.0274 ^2/4) * v

v = 0.47 m/s

Speed of the water leaving the end of the hose = 0.47 m/s.

b) Diameter of nozzle = Diameter of hose/3

= 0.0274/3

Diameter of nozzle  = 0.00913 m

Q = Av

$$2.78 * 10^{-4} = (\pi * 0.00913 ^2/4) * v

v = 4.25 m/s

Speed of the water leaving the end of the nozzle = 4.25 m/s

To learn more about Speed refer to:

brainly.com/question/4931057

#SPJ4

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