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MAVERICK [17]
3 years ago
10

Find the maximum value and minimum value in milesTracker. Assign the maximum value to maxMiles, and the minimum value to minMile

s. Sample output for the given program:Min miles: -10Max miles: 40#include using namespace std;int main( ) { const int NUM_ROWS = 2; const int NUM_COLS = 2; int milesTracker[NUM_ROWS][NUM_COLS]; int i = 0; int j = 0; int maxMiles = -99; // Assign with first element in milesTracker before loop int minMiles = -99; // Assign with first element in milesTracker before loop milesTracker[0][0] = -10; milesTracker[0][1] = 20; milesTracker[1][0] = 30; milesTracker[1][1] = 40; /* Your solution goes here */ cout << "Min miles: " << minMiles << endl; cout << "Max miles: " << maxMiles << endl;}
Computers and Technology
1 answer:
ryzh [129]3 years ago
6 0

Answer:

Following are th program in the C++ Programming Language.

#include <iostream>//set Header files

using namespace std;//set namespace

//define main function

int main()

{

//set integer constants variable

const int NUM_ROWS = 2;

//set integer constants variable

const int NUM_COLS = 2;

//set integer type array

int milesTracker[NUM_ROWS][NUM_COLS];

//set integer type variable and initialize to 0

int i = 0;

//set integer type variable and initialize to 0

int j = 0;

//set integer type variable and initialize to -99

int maxMiles = -99;

//set integer type variable and initialize to -99

int minMiles = -99;

//initialize the value in the two dimensional array

milesTracker[0][0] = -10;

milesTracker[0][1] = 20;

milesTracker[1][0] = 30;

milesTracker[1][1] = 40;

//here is the solution  

maxMiles = milesTracker[0][0];

minMiles = milesTracker[0][0];

/*set for loop to find the minimum miles and maximum miles*/

for (i = 0; i < NUM_ROWS; i++)

{

 for (j = 0; j < NUM_COLS; j++)

 {

 //set if condition for maxMiles is the bigger than

   if (milesTracker[i][j] > maxMiles)

   //initialize milesTracker[i][j] to maxMiles

     maxMiles = milesTracker[i][j];

   //set if condition for minMiles is the smaller than

   if (milesTracker[i][j] < minMiles)

   //initialize milesTracker[i][j] to maxMiles

     minMiles = milesTracker[i][j];

 }

}

//print output

cout << "Min miles: " << minMiles << endl;

//print output

cout << "Max miles: " << maxMiles << endl;

return 0;

}

<u>Output:</u>

Min miles: -10

Max miles: 40

Explanation:

Here, we define the main method and inside it:

  • set two constant integer type variable and initialize to 2
  • set integer type two-dimensional array and pass constant variables in it.
  • Set two integer type variable and initialize to 0 then, again set two integer type variable and initialize to -99.
  • Initialize the values in the two-dimensional array.
  • Set two for loop for the two-dimensional array to find the minimum and maximum miles.
  • Set two if condition to find bigger or smaller miles.

Finally, print the maximum and the minimum miles then, return 0.

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Create a Rational number class in Java using the same style as the Complex number class created in class.(The in class example c
Elis [28]

Answer:

Explanation:

/*

*    This program adds, subtracts, multiplies, and divides two rational numbers.

*/

public class Main {

  //Main method

   public static void main(String[] args) {

       Rational a = new Rational(3, 4);   // input for first rational number

       Rational b = new Rational(2 , 5);   // input for second rational number

       System.out.println(a + " + " + b + " = " + a.add(b));

       System.out.println(a + " - " + b + " = " + a.sub(b));

       System.out.println(a + " * " + b + " = " + a.mul(b));

       System.out.println(a + " / " + b + " = " + a.div(b));

   }

}

class Rational {

   public Rational(int num, int den) {

      numerator = num;

      denominator = den;

     

      //ensures a non-zero denominator

      if (den == 0)

          den =1;

     

      //stores a negative sign in numerator

      if (den < 0) {

          num = num * -1;

          den = den * -1;

      }

   }

   //return numerator

   public int getNumerator() {

     

      return numerator;

   }

 

   //return denominator

   public int getDenominator() {

     

      return denominator;

   }

 

   //return reciprocal method

   public Rational reciprocal() {

     

      return new Rational(denominator, numerator);

   }

   /*   Addition Class

    *        Find common denominator by multiplying the denominators

    *        Store number values (numerator / common denominator) as num1 and num2

    *        Sum both numbers

    */

   public Rational add(Rational r2) {

      int comDen = denominator * r2.getDenominator();

      int num1 = numerator * r2.getDenominator();

      int num2 = r2.getNumerator() * denominator;

      int sum = num1 + num2;

      return new Rational (sum, comDen);

   }

   //Subtraction Class - same implementation as Addition Class

   public Rational sub(Rational r2) {

   

     int comDen = denominator * r2.getDenominator();

     int num1 = numerator * r2.getDenominator();

     int num2 = r2.getNumerator() * denominator;

     int difference = num1 - num2;

     return new Rational (difference, comDen);

  }

   

  /*   Multiplication Class

   *        Multiply numerator with r2 numerator

   *        Multiply denominator with r2 denominator

   */

  public Rational mul(Rational r2) {

   

     int num = numerator * r2.getNumerator();

     int den = denominator * r2.getDenominator();

     return new Rational (num, den);

  }

  /*   Divide Class

   *        Multiply number by r2 reciprocal

   */

  public Rational div(Rational r2) {

      return mul (r2.reciprocal());

  }

  /*   toString Method

   *        Returns rational number as a string - in parenthesis if a fraction

   */

  public String toString() {

     

      return (((numerator == 0) ? "0" : ( (denominator == 1) ? numerator + "": "(" + numerator + "/" + denominator + ")")));

 

      /* Logic for toString method

      * if (num == 0) {

              return "0";

          } else {

              if (denominator == 1){

                  return numerator;

              } else {

                  return numerator + "/" + denominator;

              }

      */

   }

  // Declare variables

  private int numerator, denominator;

 

}

output

(3/4) + (2/5) = (23/20)                                                                                                                                      

(3/4) - (2/5) = (7/20)                                                                                                                                      

(3/4) * (2/5) = (6/20)                                                                                                                                      

(3/4) / (2/5) = (15/8)                                                                                                                                      

6 0
3 years ago
What is the downside of wider channel bandwidth?
Lana71 [14]

Answer: Wider channel bandwidth has several downside or disadvantages to it. Some of these are as follow:

a) Higher channel bandwidth means lower will be the number of channels being utilized.

b) Wider bandwidth may lead to an increase in the speed but on the other hand, it'll lead to several interference problems.

6 0
3 years ago
Given the code that reads a list of integers, complete the number_guess() function, which should choose a random number between
Cerrena [4.2K]

Answer:

see explaination

Explanation:

import random

def number_guess(num):

n = random.randint(1, 100)

if num < n:

print(num, "is too low. Random number was " + str(n) + ".")

elif num > n:

print(num, "is too high. Random number was " + str(n) + ".")

else:

print(num, "is correct!")

if __name__ == '__main__':

# Use the seed 900 to get the same pseudo random numbers every time

random.seed(900)

# Convert the string tokens into integers

user_input = input()

tokens = user_input.split()

for token in tokens:

num = int(token)

number_guess(num)

5 0
4 years ago
one day when rahul went to his computer lab and saw that all the computers were connected to a single printer and whoever is giv
amm1812

Explanation:

you can connect multiple PCs to the wireless printer and print your documents from each one of them as long as the printer can be connected to the same network . You need the disc that came with the wireless printer to install the correct drivers on your computers and laptops.

hope it helps ( brainleist please )

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Compose an e-mail to your coworker Adam that describes how to add a photograph to a slide.
pantera1 [17]

The ways to add a photograph to a slide is given below: What to write when composing the email is also given below.

<h3>How do you Insert photos into a slide?</h3>

The steps are given below?\

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  • then click on Insert menu, and take the cursor to the Picture, and then one can click Photo Browser or insert pictures.
  • Then select the picture that you want and and one can drag it onto the slide.

Note that it is essential to follow the steps and one can add as many pictures as they want to their slides.

Learn more about e-mail from

brainly.com/question/24506250

#SPJ1

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