Question

PLEASE HELP ME!! D:

Answer 1

Answer:

Point-slope form:

$y-0=\frac{1}{3} (x-1)\\f(x)-0=\frac{1}{3}(x-1)$

Slope-intercept form:

$y=\frac{1}{3}x-\frac{1}{3} \\f(x)=\frac{1}{3} x-\frac{1}{3}$

Step-by-step explanation:

You have points on that line at (-2, -1) and (1, 0). To find your slope using those points, use the slope formula.

$\frac{y2-y1}{x2-x1} \\\\\frac{0-(-1)}{1-(-2)} \\\\\frac{0+1}{1+2} \\\\\frac{1}{3}$

Now that we have your slope, you can use your slope and one of your points to write an equation in point-slope form.

$y-y1=m(x-x1)\\y-0=\frac{1}{3} (x-1)\\y=\frac{1}{3} x-\frac{1}{3}$

To put it in function notation, substitute y for f(x).

$f(x)-0=\frac{1}{3} (x-1)\\f(x)=\frac{1}{3} x-\frac{1}{3}$

Answer 2

First answer is y+1=(1/3) (x+2)

Second answer is f(x) =(1/3) x-(1/3)