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zloy xaker [14]

3 years ago

7

The goal of quality assurance is toprovide management with the data needed to determine whichsoftware engineers are producingthe

most defects.
i. True

ii. False

Computers and Technology

1 answer:

Ymorist [56]3 years ago

8 0

The answer to your question is true

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What do the following standards cover?

steposvetlana [31]

Answer:

ANSI/TIA/EIA-570-B - Residential telecommunications

ANSI/TIA/EIA-606-A - Administration

ANSI/TIA/EIA-607 - Grounding and Bonding

Explanation:

The first standard is generally used for residential telecommunication. This is mainly for the form of telecommunications used in residential areas. The second standard is mainly used for administrative purposes such as those in offices. Furthermore, the third standard is applicable to grounding and bonding purposes.

8 0

3 years ago

What Is The First Computer Brought In Nepal ? <br>

tiny-mole [99]

Answer:

I don't know,,,(((:lol

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2 years ago

D. What is the work of the following features:<br>1. Foot note

Bess [88]

Answer:

In footnotes, information is separated by commas, while in the bibliography, it is separated by periods.

In footnotes, the author's first name is listed first, while in the bibliography, the author's last name is listed first.

The titles of books and journals are put in italics.

The titles of articles are put in quotation marks.

All key words in titles are capitalized.

Explanation:

3 0

2 years ago

Suppose users share a 1-Gbps link. Also, suppose each user requires 200 Mbps when transmitting, but each user only transmits 30

V125BC [204]

Answer:

The answer is "5 users and 1 block".

Explanation:

In Option a:

Bandwidth total $= 1-Gbps \times 1000$

$= 1,000 \ Mbps$

Any User Requirement $= 200 \ Mbps$

The method for calculating the number of approved users also is:

Now, calculate the price of each person for overall bandwidth and demands,

$\text{Sponsored user amount} = \frac{\text{Bandwidth total}}{\text{Each user's requirement}}$

$=\frac{1000}{200}\\\\=\frac{10}{2}\\\\= 5 \ users$

In Option b:

$\text{blocking probability} = \frac{link}{\text{1-Gbps} = 10^9 \frac{bits}{sec}}$

$\ let = 0.05 = \frac{100}{20} \\\\\text{blocking probability} = \frac{ 200 \times 10^6}{\frac{100}{20}}$

$= \frac{ 200 \times 10^6 \times 20 }{100}\\\\= \frac{ 2 \times 10^6 \times 20 }{1}\\\\= 40 \times 10^6 \\\\$

mean user $= 25 \times \frac{1}{20} \\\\$

$= 1.25$

max user $= \frac{10^9}{40 \times 10^6} \\\\$

$= \frac{10^9}{4 \times 10^7} \\\\ = \frac{10^2}{4} \\\\ = \frac{100}{4} \\\\= 25 \\\\ =\ \ 1 \ \ block \\\\$

3 0

3 years ago

In NumPy, the_______

Nikolay [14]

Numpy is among the most prevalent science computer science bundles in Python, and the following are the discussion on the use of transpose function:

Transpose() is among the most important <em>matrix multiplication functions</em>.
It is used to changes elements of the <em><u>row into column</u></em> elements and the elements of the <em><u>column into rows</u></em> elements.
The output of this function is an original modified array.

Therefore, the transpose function in NumPy is being used to <em><u>switch positions of rows to columns or columns to rows</u></em>.

Learn more:

brainly.com/question/24763535

7 0

1 year ago