* Main Electron a component- vacuum tube.
* Main memory- Magnetic drums and magnetic tapes.
* Programming language- Machine language.
* Power- Consume a lot of electricity and generate a lot of heat.
* were expensive to operate
you can install a 64 bit operating system on a 32 bit machine.
hope this helps!
Shuffle (A[1..m], B[1..n], C[1..m+n]):
Shuf[0, 0] ← True
for j ← 1 to n
Shuf[0, j] ← Shuf[0, j − 1] ∧ (B[j] = C[j])
for i ← 1 to n
Shuf[i, 0] ← Shuf[i − 1, 0] ∧ (A[i] = B[i])
for j ← 1 to n
Shuf[i, j] ← False
if A[i] = C[i + j]
Shuf[i, j] ← Shuf[i, j] ∨ Shuf[i − 1, j]
if B[i] = C[i + j]
Shuf[i, j] ← Shuf[i, j] ∨ Shuf[i, j − 1]
return Shuf[m, n]
The algorithm runs in O(mn) time.
Answer:
import java.util.Arrays;
import java.util.Scanner;
public class num4 {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.println("How many numbers? ");
int n = in.nextInt();
int []intArray = new int[n];
//Entering the values
for(int i=0; i<intArray.length;i++){
System.out.println("Enter the numbers");
intArray[i]=in.nextInt();
}
System.out.println(Arrays.toString(intArray));
int min =intArray[0];
for(int i =0; i<intArray.length; i++){
if(min>intArray[i]){
min = intArray[i];
}
}
System.out.println("The Minimum of the numbers is "+min);
}
}
Explanation:
- Using Java programming language
- Prompt the user for the number of values
- Using Scanner class receive and store in a variable
- Create an array of size n
- Using an for loop continuously ask the user to enter the integers
- Print the array of integers
- Using another for loop with an if statement, find the smallest element in the array of numbers
- Output the the smallest number
Simple, really. No hacks required. Just study and you'll do fine.
