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finlep [7]
3 years ago
6

How many liters will 10.0 grams of hydrogen occupy at stp​

Chemistry
1 answer:
Dmitrij [34]3 years ago
4 0

Answer:

38.36 L.

Explanation:

  • We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of H₂ in atm (P = 1.0 atm, STP conditions).

V is the volume of H₂ in L (V = ??? L).

n is the no. of moles of H₂ in mol (n = mass/molar mass = (10.0 g)/(2.0 g/mol) = 5.0 mol).

R is the general gas constant (R = 0.0821 L.atm/mol.K),

T is the temperature of H₂ in K (T = 0.0°C + 273 = 273.0 K, STP conditions).

<em>∴ V = nRT/P</em> = (5.0 mol)(0.0821 L.atm/mol.K)(273.0 K)/(1.0 atm) = <em>38.36 L.</em>

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Answer:

The answer to your question is: yield = 56.27%

Explanation:

Data

             CH3CH2CH2CH2OH (l) → CH3 CH2CH2CH2Br

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              15.02 g of 1- butanol -------------   x

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