Answer: Theoretical Yield = 0.2952 g
Percentage Yield = 75.3%
Explanation:
Calculation of limiting reactant:
n-trans-cinnamic acid moles = (142mg/1000) / 148.16 = 9.584*10⁻⁴ mol
pyridium tribromide moles = (412mg/1000) / 319.82= 1.288*10⁻³ mol
- n-trans-cinnamic acid is the limiting reactant
The molar ratio according to the equation mentioned is equals to 1:1
The brominated product moles is also = 9.584*10⁻⁴ mol
Theoretical yield = (9.584*10⁻⁴ mol) * (Mr of brominated product)
= (9.584*10⁻⁴ mol) * (307.97) = 0.2952 g
Percentage Yield is : Actual Yield / Theoretical Yield = 0.2223/0.2952
= 75.3%
Answer is: H₃PO₄.
A
phosphoric acid is three protic acid, which means that in water release tree
protons. Phosphoric acid ionizes in three steps in water.
<span>
First step: H</span>₃PO₄(aq) ⇄ H₂PO₄⁻(aq) + H⁺(aq).<span>
Second step: H</span>₂PO₄⁻(aq)⇄ HPO₄²⁻(aq) + H⁺(aq).<span>
Third step: HPO</span>₄²⁻(aq) ⇄ PO₄³⁻(aq) + H⁺(aq).<span>
Species that are present: H</span>₃PO₄,
H₂PO₄⁻, HPO₄²⁻, PO₄³⁻ and H⁺, but because the acid dissociation constants are low, very low percentage of acid dissociates.