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3 years ago

Given 2 points on a graph, write the equation of the graph. Vertex (3,5). Point(5, -3)

1 answer:

4 0

We know that
for
y=a(x-h)^2+k
vertex is (h,k)
given vertex is (3,5)
y=a(x-3)^2+5
we are also given
(5,-3)
x=5 and y=-3 is a possible solution

-3=a(5-3)^2+5
-3=a(2)^2+5
minus 5 both sides
-8=a(4)
-8=4a
divide by 4 both sides
-2=a

the equation is
$y=-2(x-3)^2+5$

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Katy is walking toward a bridge. See full question below

oksano4ka [1.4K]

Answer:

Step-by-step explanation:

No c

as she was initially 300m away from the bridge (distance from bridge=300m) (time=0) so it was her starting point.

and after 6 minutes (time=6min) she reached the bridge. (distance from bridge = 0m)

5 0

3 years ago

Read 2 more answers

Let ρ = x3 + xe−x for x ∈ (0, 1), compute the center of mass.

hram777 [196]

The center of mass is mathematically given as

$\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$

<h3>What is the center of mass.?</h3>

Determine the center of mass in one dimension:

Represent the masses at the respective distances.

$\begin{|c|c|} Masses \ & \ \ \ \ \ \ \ \ \ \ \ \ \ \ Located at \\\rho=x^{3}+x \cdot e^{-x} & \ \ \ \ x \in(0,1)$ \\\end$

We calculate the total mass of the system.

$\begin{aligned}m &=\int_{0}^{1} \rho \cdot d x \\& m =\int_{0}^{1}\left(x^{3}+x \cdot e^{-x}\right) \cdot d x \\&m =\left|\frac{x^{4}}{4}-(x+1) e^{-x}\right|_{0}^{1} \\&m =\left(\frac{5}{4}-\frac{2}{e}\right)\end{aligned}$

Step 03: Calculate the moment of the system.

$\begin{aligned}M &=\int_{0}^{1}(\rho \cdot x) \cdot d x \\& M=\int_{0}^{1}\left(x^{4}+x^{2} \cdot e^{-x}\right) \cdot d x \\&M =\left|\frac{x^{5}}{5}-\left(x^{2}-2 x+2\right) \cdot e^{-x}\right|_{0}^{1} \\&M=\left(\frac{11}{5}-\frac{5}{e}\right)\end{aligned}$

we calculate the center of mass.

$\begin{aligned}\bar{x} &=\left(\frac{M}{m}\right) \\& \bar{x}=\left\{\left(\frac{\left.11-\frac{5}{5}\right)}{\left(\frac{5}{4}-\frac{2}{e}\right)}\right\}\right.\\& \bar{x}=\left(\frac{11 e-25}{5 e}\right) \cdot\left(\frac{4 e}{5 e-8}\right) \\&\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$

Read more about the center of mass.

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8 0

2 years ago

If the factors of quadratic function g are (x − 7) and (x + 3), what are the zeros of function g?

MArishka [77]

Answer: B. -3 and 7

Step-by-step explanation:

To find the zeros, just move the constants to the other side,

x - 7 ⇒ x = 7

x + 3 ⇒ x = -3

If the number is moved to the other side its sign becomes opposite

Hope it helps!

8 0

2 years ago

This is a proportion. What is the value of X?

Verizon [17]

Answer:

x = 15 or x = - $\frac{2}{5}$

Step-by-step explanation:

Cross- multiplying gives

(14x + 6)(17x + 5) = 9x(27x + 11) ( expanding factors )

238x² + 172x + 30 = 243x² + 99x

rearrange into standard form : ax² + bx + c = 0

5x² - 73x - 30 = 0 ← in standard form

consider the factors of the product 5 × - 30 = - 150 which sum to the coefficient of the x-term (- 73 )

the factors are - 75 and + 2

Use these factors to split the middle term

5x² - 75x + 2x - 30 = 0 ( factor by grouping )

5x(x - 15) + 2(x - 15) = 0 ← take out the factor (x - 15)

(x - 15)(5x + 2) = 0

equate each factor to zero and solve for x

x - 15 = 0 ⇒ x = 15

5x + 2 = 0 ⇒ x = - $\frac{2}{5}$

7 0

3 years ago

-2(3x-1)<8 on a number line

Veronika [31]

Answer:

Checkout the image below the explanation.

Step-by-step explanation:

1. First, let's solve the inequality.

Step 1: Simplify both sides of the inequality.

$-6x + 2 < 8$

Step 2: Subtract 2 from both sides.

$-6x + 2 - 2 < 8 - 2$
$-6x < 6$

Step 3: Divide both sides by -6 and flip the sign.

$\frac{-6x}{-6} < \frac{6}{-6}$
$x > -1$

2. Now that we solved the inequality and got x > -1, that means that all values of x are more than -1. It can be represented on the number-line as this:

7 0

2 years ago