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Jobisdone [24]
2 years ago
7

1) How many Joules of energy are released when 75g of water is heated

Chemistry
1 answer:
Pie2 years ago
8 0

Answer: 23,199 J

Explanation:

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For the reaction 2 HCl + Ca ( OH ) 2 ⟶ CaCl 2 + 2 H 2 O how many grams of calcium hydroxide, Ca(OH)2, are needed to react comple
kari74 [83]

Answer: 65.38g of Ca(OH)2 is needed

Explanation:

From The equation of reaction

2 HCl + Ca ( OH ) 2 ⟶ CaCl 2 + 2 H 2 O

NB: Molar mass of HCl= 1+35.5=36.5

Ca(OH)2= 74

From The stoichiometric equation

2mol of HCl(36.5×2=73) require 1mol of Ca(OH)2 (74g)

Hence 64.5g of HCl will require 64.5×74/73= 65.38g of Ca(OH)2

5 0
3 years ago
It is necessary to know the time of day and the position of the Sun or the stars relative to one's longitude line because ____.
allochka39001 [22]

Answer: the longitude line rotates with Earth, 360 degrees in 24 hours.

Explanation: In the old days, the position of the sun was used to tell which time of the day it is. But more modern findings, has shown that the longitude line matters too.

3 0
3 years ago
What is the pH of an acid with a [H+] of 1.0 x 10&amp;-4 M?<br><br> 1. 4<br> 2. 10<br> 3. 1<br> 4. 7
True [87]
PH scale is from 1 to 14 and indicates how acidic or basic a solution is. To find pH or pOH we need to know the H⁺ ion concentration or OH⁻ concentration.
pH can be calculated using the following equation;
pH = -log[H⁺]
the H⁺ concentration of the given acid is 1.0 x 10⁻⁴ M. substituting this we can find the pH 
pH = -log[1x10⁻⁴]
pH = 4
answer is 1) 4
3 0
3 years ago
The edge length of the unit cell of KCl (NaCl-like structure, FCC) is 6.28 Å. Assuming anion-cation contact along the cell edge,
Mila [183]

Answer:

1.33 Å

Explanation:

Given that the edge length , a of the KCl which forms the FCC lattice = 6.28 Å

Also,

For the FCC lattice in which the anion-cation contact along the cell edge , the ratio of the radius of the cation to that of anion is 0.731.

Thus,

\frac {r^+}{r^-}=0.731 .................1

Also, the sum of the radius of the cation and the anion in FCC is equal to half of the edge length.

Thus,

r^++r^-=\frac {a}{2}  ...................2

Given that:

Cl^-\ (r^-) = 1.82\ \dot{A}

To find,

K^+\ (r^+) = ? \dot{A}

Using 1 and 2 , we get:

1.731\ r^+=0.731\times \frac {6.28}{2}

<u>Size of the potassium ion = 1.33 Å</u>

4 0
3 years ago
Another name for chemical change
elena-14-01-66 [18.8K]
Another name for chemical change would be chemical reaction.
8 0
4 years ago
Read 2 more answers
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