Answer:The volume of the remaining gas that is ammonia is 23.85 L.
Explanation:

Moles of 
Moles of HCl of gas = 
According to reaction 1 mole of HCl reacts with 1 mol of
then 2.06 moles of HCl will react with = 2.06 moles of
Moles left of ammonia left = 4.43 - 2.06 = 2.36 moles
Volume of the gas will be given by Ideal gas equation: PV=nRT
Pressure = 752 mmHg = 752 × 0.0031 atm = 2.33 atm
R = 0.08026 L atm/K mol
V = ? , n = number of moles of ammonia
Temperature = 14 °C = 14 + 273 K = 287 K(0°C = 273K)

The volume of the remaining gas that is ammonia is 23.85 L.
Answer: b) positron
Explanation:
The antiparticle or the antimatter counterpart of the electron is called positron.
The positron has an electric charge of +1 e and same mass as an electron. When a positron collides with an electron, annihilation takes place.
Below is an attachnent that further explains this
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Answer:
mass is 4.57 g
Explanation:
Ca(OH)₂ solution consists of Ca(OH)₂ solute molecules and solvent and we are asked to find the mass of Ca(OH)₂ in the solution
number of moles of Ca(OH)₂ is - 0.0787 mol
molar mass of Ca(OH)₂ is - 58.093 g/mol
we can use the following equation
number of moles = mass of Ca(OH)₂ / molar mass of Ca(OH)₂
rearranging the equation
mass of Ca(OH)₂ = number of moles x molar mass
mass = 0.0787 mol x 58.093 g/mol = 4.57 g
mass of Ca(OH)₂ is 4.57 g