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jok3333 [9.3K]
3 years ago
5

What's the least common denominator of 3⁄4, 4⁄5, and 2⁄3?

Mathematics
2 answers:
Gnesinka [82]3 years ago
6 0
Because 5 is in this set, you can already exclude B. 2's factors can not be odd, so that excludes D. and 3's factors doesn't include 20, so you can exclude A.

Answer would be C.
Cloud [144]3 years ago
6 0

Answer:

Option (c) is correct.

least common common denominator is 60.

Step-by-step explanation:

Given  numbers are \frac{3}{4} \ ,\ \frac{4}{5} \ , \frac{2}{3}

We have to find the least common denominator for the given numbers.

least common number is the greatest value that is multiple of all the given numbers.

Since, denominator of given fractional numbers are 3, ,4 ,5

So least common denominator is the number that is multiple of all the given denominator.

Since, 3  = 3 × 1

4 =  2 ×  2

5 = 5 × 1

Least common number is find by multiplying all the factors and taking common factor one time.Since, 3, 4, 5 do not have any factor in common

So, the product of  3, 4, 5 are the least common denominator

thus, 3 ×  4 × 5 = 60

Thus, least common common denominator is 60.

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Proved Below

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\sf \frac{3}{m+4} - \frac{4}{m} = 6\\LCM = m(m+4)\\Multiplying \ both \ sides \ by\ m(m+4)\\3m - 4(m+4) = 6m(m+4)\\3m-4m-16 = 6m^2+24m\\-m-16 = 6m^2+24m\\Adding\ m\ to\ both\ sides\\-16 = 6m^2+24m+m\\-16 = 6m^2+25m\\Adding \ 16 \ to \ both \ sides\\0 = 6m^2+25m+16\\OR\\6m^2+25m+16 = 0

Hence, Proved that \sf \frac{3}{m+4} - \frac{4}{m} = 6 is equivalent to \sf 6m^2+25m+16 = 0.

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