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3 years ago

Solve the given differential equation by separation of variables. dy dx = xy + 5x − y − 5 xy − 2x + 6y − 12

Mathematics

1 answer:

Solnce55 [7]3 years ago

3 0

solution:

Consider the differential equation DE

Dy/dx = xy + 5x –y -5 /xy -2x + 6y -12

Write the DE as the follows.

Dy/dx = x(y+5) -1(y+5)/x(y-2) +6(y-2)

Dy/dx = (x-1) (y+5)/(x+6)(y-2)

Separate the variables.

y-2/y+5 dy = x-1/x+6 dx

integrate on the both sides,

∫y-2/y+5 dy = ∫x-1/x+6 dx

7in(x+6) -7in(y+5) = x-y+c

In(x+6)∧7 –in(y+5)∧7 = x-y+c , using bIna =Inab

In [(x+6)∧7/(y+5)∧7] = x-y+c ,using Ina – Inb = In(b/a)

eIn[(x+6)∧7/(y+5)∧7] = ex-y+c , taking exponents on both sides

(x+6)∧7/(y+5)∧7 = ec.ex-y ,use eInx = x

(x+6)∧7/(y+5)∧7 = c1ex-y , take ec =c1

Hence, the solution of the DE is (x+6)∧7/(y+5)∧7 = c1ex-y

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If the standard deviation of an exam is 5, the z-score us 1.95 and the mean is 80; what is the actual test score? (Round the ans

skad [1K]

If the standard deviation of an exam is 5, the z-score us 1.95 and the mean is 80, the actual test score is; 89.75

<h3>How to solve z-score problems?</h3>

We are given;

Standard deviation; s = 5

z-score = 1.95

Mean = 80

Formula for z-score is;

z = (x' - μ)/σ

Thus;

1.95 = (x' - 80)/5

1.95 * 5 = (x' - 80)

9.75 = x' - 80

x' = 80 + 9.75

x' = 89.75

Read more about Z-score Problems at; brainly.com/question/25638875

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6 0

2 years ago

How many solutions does the system have?

sertanlavr [38]

If a solution(s) exists y=y so we can say:

x^2-3x=-2x+2 add 2x to both sides

x^2-x=2 subtract 2 from both sides

x^2-x-2=0 factor

(x-2)(x+1)=0

So x=-1 and 2, using y=-2x+2 we find:

y(-1)=4 and y(2)=-2

So the two solutions occur at the points:

(-1,4) and (2,-2)

4 0

3 years ago

Read 2 more answers

A set of city temperatures in April are normally distributed with a mean of 19.7 degrees Celsius and a standard deviation of 2 d

Sati [7]

Answer:

19.77% of average city temperatures are higher than that of Cairo

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 19.7, \sigma = 2$