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oksano4ka [1.4K]
3 years ago
14

Find the point of intersection of the two lines y=3x+2 and y=2x-1

Mathematics
2 answers:
lys-0071 [83]3 years ago
5 0
Basically the point of intersection is where the values of x and y are equal in both equations. In the first equation y is 3x+2. Substitute y in th second equation with 3x+2. The value of x is - 3. Do th same to get the value of y, which is - 7
inessss [21]3 years ago
4 0
(-3,-7) because the two lines have different slopes an the point that they intersect is the point i listed above
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Can someone please tell me the answers to the last two questions please
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Are you supposed to estimate or get an exact answer? If you're estimating you can see if the number is close to any perfect squares. In this case 63 is very close to 64, and 48 is very close to 49. The answers can then be estimated to be approximately 8 and 7, respectively.
6 0
3 years ago
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What is the probability that a person who is above 35 years old has a hemoglobin level of 9 or above?
lorasvet [3.4K]

Answer:

Option C. P=0.531

Step-by-step explanation:

we know that

The probability of an event is the ratio of the size of the event space to the size of the sample space.  

The size of the sample space is the total number of possible outcomes  

The event space is the number of outcomes in the event you are interested in.  

so  

Let

x------> size of the event space  (total person's hemoglobin level of 9 or above with age above 35 years)

y-----> size of the sample space  (total person's age above 35 years)

so

P=\frac{x}{y}

In this problem we have

y=162

Complete the table to find the total person's hemoglobin level of 9 or above (person's age above 35)

Let

y------> total person's hemoglobin level between 9 and 11 (person's age above 35)

y+76+40=162

y=46

Find the value of x

x=46+40=86

substitute the values

P=\frac{86}{162}=0.531

4 0
3 years ago
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Assume that the probability of a defective computer component is 0.02. Components arerandomly selected. Find the probability tha
solmaris [256]

Answer:

0.0177 = 1.77% probability that the first defect is caused by the seventh component tested.

The expected number of components tested before a defective component is found is 50, with a variance of 0.0208.

Step-by-step explanation:

Assume that the probability of a defective computer component is 0.02. Components are randomly selected. Find the probability that the first defect is caused by the seventh component tested.

First six not defective, each with 0.98 probability.

7th defective, with 0.02 probability. So

p = (0.98)^6*0.02 = 0.0177

0.0177 = 1.77% probability that the first defect is caused by the seventh component tested.

Find the expected number and variance of the number of components tested before a defective component is found.

Inverse binomial distribution, with p = 0.02

Expected number before 1 defective(n = 1). So

E = \frac{n}{p} = \frac{1}{0.02} = 50

Variance is:

V = \frac{np}{(1-p)^2} = \frac{0.02}{(1-0.02)^2} = 0.0208

The expected number of components tested before a defective component is found is 50, with a variance of 0.0208.

5 0
2 years ago
1.) Jasmine earns her regular pay of $9.50 per hour for up to 40 hours of
HACTEHA [7]

Answer:

$408.25

Step-by-step explanation:

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380+28.50=

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4 0
2 years ago
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Answer:

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3 0
2 years ago
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