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3 years ago

Find the point of intersection of the two lines y=3x+2 and y=2x-1

2 answers:

5 0

Basically the point of intersection is where the values of x and y are equal in both equations. In the first equation y is 3x+2. Substitute y in th second equation with 3x+2. The value of x is - 3. Do th same to get the value of y, which is - 7

inessss [21]3 years ago

4 0

(-3,-7) because the two lines have different slopes an the point that they intersect is the point i listed above

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Please help with this Khan Question :)

astraxan [27]

Answer:

the answer is A

Step-by-step explanation:

4 0

3 years ago

Can someone explain how to do this?

Tems11 [23]

x+7
------------------- =
x^2+4x -21

x+7
= -------------------
   (x+7)(x-3)

1
= ----------  where x is not equal -7 and 3
   x - 3

answer is A. first choice

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3 years ago

3. Use the diagram 2 and 3 are ____ angles 1. complementary 2. vertical 3. right 4. supplementary

Vladimir79 [104]

2 and three are supplementary angles .

#4.

The answer is opposite angles .

Hence there is no option

Bisected angles are equal

$\\ \sf\longmapsto 5x=3x+10$

$\\ \sf\longmapsto 5x-3x=10$

$\\ \sf\longmapsto 2x=10$

$\\ \sf\longmapsto x=\dfrac{10}{2}$

$\\ \sf\longmapsto x=5$

Now

m<ABC

$\\ \sf\longmapsto 5x+3x+10$

$\\ \sf\longmapsto 8x+10$

$\\ \sf\longmapsto 8(5)+10$

$\\ \sf\longmapsto 40+10$

$\\ \sf\longmapsto 50$

5 0

3 years ago

Read 2 more answers

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Nina [5.8K]

Answer:

As x decreases in value.f(x) decreases in value.......

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3 years ago

Una compañía de telefonía móvil en expansión ha gestionado durante el trimestre que finaliza ochocientas cincuenta mil llamadas

NISA [10]

Answer:

$2,050,000\ daily\ calls$

Step-by-step explanation:

<u><em>The question in English is </em></u>

An expanding mobile phone company handled eight hundred and fifty thousand calls a day during the quarter. In the next quarter it expects to reach one million and increase quarterly by the same amount over the next two years. How many daily calls do you expect to handle in two years?

Let

x ----> the number of quarter

y ---> number of daily calls

we know that

we have the points

(0,850,000) and (1,1,000,000)

Find the slope m

$m=(1,000,000-850,000)/(1-0)=150,000\ daily\ calls$

The linear equation that represent this situation is

$y=150,000x+850,000$

How many daily calls do you expect to handle in two years?

In two years there are 8 quarterly

For x=8

substitute

$y=150,000(8)+850,000=2,050,000\ daily\ calls$

7 0

3 years ago