Answer:
2,655 students
Step-by-step explanation:
The z-score for a 99% confidence interval is z = 2.576
The standard error for a proportion p is:
![SE = z*\sqrt{\frac{p*(1-p)}{n} }](https://tex.z-dn.net/?f=SE%20%3D%20z%2A%5Csqrt%7B%5Cfrac%7Bp%2A%281-p%29%7D%7Bn%7D%20%7D)
For a proportion of p =0.20, in order to ensure a standard error of 0.02, the sample size 'n' must be:
![0.02 = 2.576*\sqrt{\frac{0.2*(1-0.2)}{n}}\\n=2,654.31](https://tex.z-dn.net/?f=0.02%20%3D%202.576%2A%5Csqrt%7B%5Cfrac%7B0.2%2A%281-0.2%29%7D%7Bn%7D%7D%5C%5Cn%3D2%2C654.31)
Rounding up to the next whole student, the sample size needed is 2,655 students.
I'm pretty sure it is.
If i'm wrong, I'm truly sorry
Answer:
-9/2, 3/5, 1
Step-by-step explanation:
Those are the answers on edginuity.
Answer:
Library's Area= 5200
Courthouse' Area= 5027
<u>Larry</u> is correct.
Step-by-step explanation: