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Korolek [52]
3 years ago
14

1. How many solitions does this equation have -4(5-3x)=12x+20

Mathematics
2 answers:
Rom4ik [11]3 years ago
6 0

Answer:

1. no solutions

2. one solution

Step-by-step explanation:

1. -4(5-3x)=12x+20

-20+12x=12x+20

-40+12x=12x

-40=0?????

So no solutions.

2. 3x+7(x+1)=2(6x+5)+2

3x+7x+7=12x+10+2

10x+7=12x+12

-2x+7=12

-2x=5

x=-5/2

So one solution.

den301095 [7]3 years ago
5 0

Answer:

The answers are:

1.  No solution.

2. One solution: x=-\frac{1}{2}

Step-by-step explanation:

In order to determine the solutions for both equations, we have to solve every one. In any equation of one variable, we could get three types of solution:

  1. One solution. The variable has a unique value.
  2. No solution. The equality is not fulfilled.
  3. Infinite solution. The variable is eliminated from the equation and the equality is fulfilled.

So, solving both equation:

1.-

-4(5-3x)=12x+20\\-20+12x=12x+20\\12x-12x=20+20\\0=40\\

The equality is not fulfilled. There is not solution.

2.-

3x+7(x+1)=2(6x+5)-2\\3x+7x+7=12x+10-2\\10x-12x=8-7\\-2x=1\\x=-\frac{1}{2}

There is one solution. x=-\frac{1}{2}

Finally, the answers for both questions are:

1.  No solution.

2. One solution: x=-\frac{1}{2}

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