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strojnjashka [21]
3 years ago
6

Help me with this??​

Mathematics
1 answer:
Mandarinka [93]3 years ago
7 0
The answer would be 2 to the 2nd power
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Simplify the numerical expression:<br> (5^4) (5^2)<br> A. 5^-10<br> B. 5^2<br> C. 5^-6<br> D. 5^-2
alexgriva [62]

Answer: A is the answer

3 0
3 years ago
In the figure below, B is the center of the circle, NL
Black_prince [1.1K]

Answer: x=12

Step-by-step explanation:

OQ is equal to NL since both contain 90 degree angles and are intersected by a radius. Since OS is 3x-2 and NL is 32, then we need to find OQ and set it equal to NL. OS is half of OQ, so multiplying OS by 2 will get you OQ. 6x-4=32

That yields x=12.

8 0
3 years ago
Read 2 more answers
A zoo collected data on the diving times of turtles. Based on the data, the regression line is j = 0.010 + 2.515x, where x is th
mariarad [96]

Answer:

6.298 meters

Step-by-step explanation:

Here, we are told that x is the time of the dive in minutes.

We simply first need to convert 150 seconds to minutes before substitution into the regression formula;

Kindly recall that 60 seconds = 1 minute

So 150 seconds will be 150/60 = 2.5 minutes

We now proceed to substitute into;

j = 0.010 + 2.515(x)

i = 0.010 + 2.515(2.5)

j = 0.010 + 6.2875

j = 6.2975 which go 3 decimal places is 6.298 meters

7 0
3 years ago
Can someone please help me???!!!
Ksju [112]

Answer:

I can't show you all of the work but you can use this to find the answer

https://www.mathsisfun.com/geometry/circle-theorems.html

5 0
3 years ago
The polynomial has the following zeros: 0, 1, -2i, 3+the square root of 3. Put the polynomial in standard form.
dimulka [17.4K]
Standard form
ok, so the factored form of a polynomial with roots r1,r2,r3,r4 is
f(x)=(x-r1)(x-r2)(x-r3)(x-r4)
so
since the roots are 0,1,-2i,3+√3
I am assuming you want real coefients so ince -2i is a root, 2i is also a root

f(x)=(x-0)(x-1)(x+2i)(x-2i)(x-(3+√3))
f(x)=x⁵-(√3)x⁴-4x⁴+(√3)x³+7x³-(4√3)x²-16x²+12x

if you were allowed to have no-real coefients then exclue the 2i
f(x)=(x-0)(x-1)(x+2i)(x-(3+√3))
f(x)=(4x^4-4x^3- \sqrt{3}x^3+\sqrt{3}x^2+3x^2)+(2x^3-8x^2-2 \sqrt{3}x^2+6x+2 \sqrt{3}x) i
6 0
3 years ago
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