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Finger [1]
3 years ago
5

Find the distance between the pair of points (0,0)(6,8)

Mathematics
1 answer:
Ivahew [28]3 years ago
4 0
  • A(0,0)
  • B=(6,8)

Distance formula

\boxed{\sf AB=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}

\\ \sf\longmapsto  \sqrt{(6 - 0) {}^{2} +  {(8 - 0)}^{2}  }  \\ \\ \sf\longmapsto  \sqrt{ {6}^{2}  +  {8}^{2} }  \\ \\ \sf\longmapsto  \sqrt{36 + 64  }  \\ \\ \sf\longmapsto  \sqrt{100}  \\ \\ \sf\longmapsto 10

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Convert to scientific notation ​
andreev551 [17]

Answer:

8.245*10^6

Step-by-step explanation:

scientific notation is known as c*10^n

c : any number from 1-10

n : the power of base 10

the number in our case between 1 and 10 is 8.245

but then we want to move the decimal 6 spaces to the right, so we multiply that by 10^6

8 0
3 years ago
Credit cards are 0.76 mm thick. How thick is a stack of 10thirds credit cards piled one on top of the other???
natima [27]
You are correct its A
3 0
3 years ago
Read 2 more answers
Which of the expressions is rational? 25 + 2 7 − 2 64 + 45
Levart [38]

Answer:

All of the expressions

Step-by-step explanation:

A rational number is one that can be written as a ratio, or a number with a terminating decimal.

All of the expressions are whole numbers, so they are all rational.

4 0
3 years ago
Write the given roots to quadraatic equation
german

Answer:

It's like solving a quadratic, but in reverse, and in this case you'll arrive at x2+x−12=0

Explanation:

We're going to go "backwards" with this problem - normally we're asked to take a quadratic equation and find the roots. So we'll do what we normally do, but in reverse:

Let's start with the roots:

x=3, x=−4

So let's move the constants over with the x terms to have equations equal to 0:

x−3=0, x+4=0

Now we can set up the equation, as:

(x−3)(x+4)=0

We can now distribute out the 2 quantities:

x2+x−12=0

6 0
3 years ago
Is anyone willing to help me with this? I tried adding this and still no answer. Please help..
GaryK [48]

Answer:   C. (-4, -2)

<u>Step-by-step explanation:</u>

First, eliminate one of the variables and solve for the remaining variable:

2x - 5y = 2      →    3(2x - 5y = 2)      →     6x - 15y = 6

3x + 2y = -16   →  -2(3x + 2y = -16)    →  <u> -6x - 4y = 32</u>

                                                                     -19y = 38

                                                                         y = -2


Next, replace "y" with -2 into either of the original equations to solve for x:

2x - 5y = 2

2x - 5(-2) = 2

2x + 10 = 2

2x         = -8

 x          = -4

                                       x = -4,  y = -2

<u>Check:</u>

Plug in the x- and y-values into the other original equation:

3x + 2y = -16

3(-4) + 2(-2) = -16

-12  +  -4     = -16

      -16         = -16   \checkmark

3 0
4 years ago
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