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3 years ago

ANSWER PLSSS!!!!!

Mathematics

2 answers:

Leni [432]3 years ago

7 0

Answer:

Step-by-step explanation:

hope this helps and if it dosent get me through the comments

Roman55 [17]3 years ago

6 0

Answer:

Step-by-step explanation:

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[URGENT] Suppose A and B are dependent events. If P(A) = 0.4 and P(B A) = 0.8, what is<br>P(A B)?

Tomtit [17]

Answer:

Option (B)

Step-by-step explanation:

If the probabilities of two events A and B are P(A) and P(B) then the conditional probability of an event that can be derived by the formula,

P(B | A) = $\frac{P(A\cap B)}{P(A)}$

P(A ∩ B) = P(B|A) × P(A)

P(A ∩ B) = (0.8) × (0.4)

= 0.32

Therefore, Option (B) will be the correct option.

8 0

3 years ago

An English professor assigns letter grades on a test according to the following scheme. A: Top 15% of scores B: Scores below the

lisabon 2012 [21]

Answer:

59 to 66

Step-by-step explanation:

Mean test scores = u = 74.2

Standard Deviation = $\sigma$ = 9.6

According to the given data, following is the range of grades:

Grade A: 85% to 100%

Grade B: 55% to 85%

Grade C: 19% to 55%

Grade D: 6% to 19%

Grade F: 0% to 6%

So, the grade D will be given to the students from 6% to 19% scores. We can convert these percentages to numerical limits using the z scores. First we need to to identify the corresponding z scores of these limits.

6% to 19% in decimal form would be 0.06 to 0.19. Corresponding z score for 0.06 is -1.56 and that for 0.19 is -0.88 (From the z table)

The formula for z score is:

$z=\frac{x-u}{\sigma}$

For z = -1.56, we get:

$-1.56=\frac{x-74.2}{9.6}\\\\ x = 59$

For z = -0.88, we get:

$-0.88=\frac{x-74.2}{9.6}\\\\ x = 66$

Therefore, a numerical limits for a D grade would be from 59 to 66 (rounded to nearest whole numbers)

7 0

4 years ago

Solve each calculation. Be sure to report your answer with the correct number of significant figures.

Serjik [45]

Question:

Solve each calculation. Be sure to report your answer with the correct number of significant figures.

5.61000 dg × 1.1010 dg

12.0 m ÷ 3.1415 m

Answer:

1. $5.61000dg * 1.1010dg$ = $6.177 dg^2$

2. $\frac{12}{3.1415} = 3.8198$

Step-by-step explanation:

1. 5.61000 dg × 1.1010 dg

We start by representing each digit using scientific notation

$5.61000 = 561000 * 10^{-5}$

$1.1010 = 11010 * 10^{-4}$

Then, Multiply both numbers

$561000 * 10^{-5} * 11010 * 10^{-4}$

First, rearrange

$561000 * 11010 * 10^{-5} * 10^{-4}$

$6176610000 * 10^{-5} * 10^{-4}$

From law of indices, $10^{-5} * 10^{-4} = 10^{-9}$ ;

So, we have

$6176610000 * 10^{-9}$

$6.176610000$

Because 5.61000 is given in 3 significant figures and 1.1010 is given in 4 significant figures, we approximate the result to 4 significant figures

This gives $6.177$