If all were children, revenue would be 700*$7 = $4900. Revenue is actually $6400 -4900 = $1500 more than that. Each adult admission that replaces a child's admission adds $10 -7 = $3 to the revenue, so there must have been
$1500/$3 = 500 . . . . adult admissions
There were 200 children at the show.
There were 500 adults at ths show.
Answer: 60= $3.00 and 30= $4.00
x=# of $3 tickets
90-x=# of $4 tickets
$3x+$4(90-x)=$300
3x+360-4x=300
-x+360=300
-x=-360+300
-x=-60
x=60 $3 tickets
90-60=30 $4 tickets
Find the critical value or test statistic.
Find P(z > 2.25) using a normal distribution table
P(z > 2.25) = 0.0122
Answer:
okay
Step-by-step explanation:
Answer:
(c) 3,5 is the correct answer
