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2 years ago

6

Help i'll give brainlist

1 answer:

kow [346]2 years ago

6 0

Answer:

y = -2

Step-by-step explanation:

The midline is the horizontal line that passes exactly in the middle between the graph's maximum and minimum points.

From inspection, curve has a maximum at y = 1 and a minimum at y = -5

The midline between these is $y=\frac{1-5}{2}=-2$

So the equation for the midline of this graph is y = -2 (shown in red on the attached graph)

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The amount of snow on the ground increased by 4 inches between 1 p.m. and 6 p.m. What integer represents the amount of snow that

scZoUnD [109]

Answer:

The snow from each event melts off before the next accumulation and no snow is on the ground at your scheduled time of observation. The total snowfall for that reporting 24-hour day is the sum of the three separate snow squalls, 6.7 inches, even though the snow depth on your board at observation time was zero. Snow often melts as it lands. your welcome!

3 0

2 years ago

cho hàm số y = f(x) có đạo hàm liên tục trên R thỏa mãn 2f(2x)+f(1-2x) = 12x2 víu mọi x thuộc R . Phương trình tiếp tuyến của đồ

Nina [5.8K]

Answer:

ask in english

Step-by-step explanation:

then I can help u

6 0

3 years ago

If a classroom has 7 students with black hair and there are 24 students in the

telo118 [61]

Answer:

29.2%

Step-by-step explanation:

The fraction of students with black hair is 7/24. To convert that to a percentage, multiply by 100%.

7/24×100% = 29.1666(repeating)% ≈ 29.2%

3 0

3 years ago

The graph of an inverse trigonometric function passes through the point (1, pi/2). Which of the following could be the equation

rodikova [14]

Answer: C) $y=sin^-1 x$

Step-by-step explanation:

Since, the graph of an inverse trigonometric function will pass through the point $(1,\frac{\pi}{2})$ ,

If this point satisfies the function,

For the function $y=cos^{-1} x$

If x = 1

$y=cos^{-1}1=0$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cos^{-1} x$ ,

⇒ The graph of $y=cos^{-1} x$ is not passing through the point $(1,\frac{\pi}{2})$

For the function $y=cot^{-1}x$

If x = 1

$y=cot^{-1}1=\frac{\pi}{4}$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cot^{-1}x$ ,

⇒ The graph of $y=cot^{-1}x$ is not passing through the point $(1,\frac{\pi}{2})$

For the function $y=sin^{-1} x$

If x = 1

$y=sin^{-1}1=\frac{\pi}{2}$

Thus, $(1,\frac{\pi}{2})$ is satisfying function $y=sin^{-1} x$ ,

⇒ The graph of $y=sin^{-1} x$ is passing through the point $(1,\frac{\pi}{2})$ .

For the function $y=tan^{-1}x$

If x = 1

$y=tan^{-1}1=\frac{\pi}{4}$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cos^{-1} x$ ,

⇒ The graph of $y=tan^{-1} x$ is not passing through the point $(1,\frac{\pi}{2})$ .

Hence, Option C is correct.

3 0

3 years ago

Which expression shows 48+36 written as a protuct of two factors

nirvana33 [79]

Answer:

12(4+3)

Step-by-step explanation:

Factor out all of the problems.

Starting with 4(12+4)

This means (4*12)+(4*4)

48+16 is the answer to this

this isn't 48 + 36

12(4+3) is next

12*4 = 48

12*3 = 36

48+36 = 48 + 36

Therefore 12(4+3) is your answer

hope that helps!

hope this is what your looking for

8 0

2 years ago