Answer:

Step-by-step explanation:
Given
The attached graph
Required

This is the point where

On the attached graph;
when 
Hence:

Answer: c. (1/2) bc sin A
<u>Step-by-step explanation:</u>
You can find the area of a triangle using trigonometry if you know the lengths of two sides and the measure of the included angle using the following formula:

I wrote the domain and range in interval notation, not sure if that’s how you’re asked to do it. This is how I was taught to state the domain/range of a graph.
First solve for the other angles.
You know one angle is 15º.
The one across from it is also 15º since it is a vertical angle to the known 15º angle.
Both of those together gets 30º.
The whole thing is 360º, so just subtract 30 from 360 and divide.
360 - 30 = 330
Do the same for the 15x angle.
The one under/across to it is a vertical angle so is also 15xº.
Now you are left with 30xº = 330.
Just divide now.
330 / 30 = 11
x = 11
15x = 165
Checking your work:
15x = 165
15x = 165
15
15
Those are the angles.
Add those numbers together and make sure it adds up to 360º.
165 + 165 + 15 + 15 = 360
So this is correct.
Answer:
z=3 because in the 2(z+3) is like (z+2)+(z+6)