Answer:
There were 7 small boxes and 14 large boxes shipped.
Step-by-step explanation:
This problem may be solved by a system of equations:
I am going to say that:
x is the number of small boxes used
y is the number of large boxes used
There were twice as many large boxes shipped as small boxes shipped
This means that y = 2x
Each small box of paper weighs 45 pounds and each large box of paper weighs 80 pounds. The total weight of all boxes was 1435 pounds.
This means that 45x + 80y =1435
So we have to solve the following system:
y=2x
45x + 80y =1435
45x + 80 (2x) = 1435
205x = 1435
x= 1435/205
x=7
y=2x= 2(7) = 14
There were 7 small boxes and 14 large boxes shipped.
The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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Yes D is the correct option !
if you want to know how , comment, or you are good to go !
Answer:
$594.03
Step-by-step explanation:
Using the exponential function;
A = Pe^-rt
Principal = $960
Rate r = 12% = 0.12
Time t = 4years
Substitute
A = 960e^-(0.12*)*4
A = 960e^-0.48
A = 960(0.61878)
A = 594.03
HEnce the worth after 4years will be $594.03
The answer is $31 dollars because there is 31 days in August
