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3 years ago

Evaluate a-b²c2 for a = 2, b = 3, and c = 4.

Mathematics

2 answers:

katrin2010 [14]3 years ago

4 0

Answer: -70

Step-by-step explanation: 2-3^2x4x2

AlekseyPX3 years ago

3 0

Answer: -70

Step-by-step explanation:

1. Write out equation : 2-3^2(4)(2)

2. PEMDAS = (Exponents) 3 to the second power = 9

3. 2-9(4)(2)

4. Multiply 9 & 4 which is 36 then multiply

36 & 2 which is 72

5. 2-72

6. -70

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Kenya exchange $200 for euros (€) suppose the conversion rate is €1 = $1.321 how many euros should kenya recieve?

____ [38]

Since 1 Euro is 1.321 in American money you must convert the value to $200
Divide 200 by 1.321
you get
151.40 in Euros

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2 years ago

(60)x = 1, what are the possible values of x? Explain your answer.

Gnesinka [82]

Answer:

$\frac{1}{60}$

Step-by-step explanation:

Problem:

The possible values of x in the equation (60)x = 1;

Solution:

Such a problem like this in which the highest power of the unknown is 1 will have just one solution.

60x = 1

To solve this, we take the multiplicative inverse of 60;

the multiplicative inverse of 60 = $\frac{1}{60}$

Use this inverse to multiply both sides of the expression;

$\frac{1}{60}$ $x$ 60x = 1 x $\frac{1}{60}$

x = $\frac{1}{60}$

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2 years ago

larry used 84% of his money in his savings account to buy a dirt bike that costs 1,050. how much money is left in the acount aft

Bogdan [553]

The answer should be either b or d but i’m not too sure

7 0

3 years ago

Read 2 more answers

HELP ME!! SOMEBODY PLEASE HELP ME

IRISSAK [1]

6^2 = x (x - 9)
x^2 - 9x - 36 = 0
(x -12)(x + 3) = 0
x - 12 = 0; x = 12
x +3 = 0; x = -3

so in this case x = 12 then DC = 12 - 9 = 3

y^2 = 12^2 - 6^2
y^2 = 144 - 36
y^2 = 108
y = 10.4

4 0

3 years ago

Help appreciated on question in image!<br> Thanks:)

Verdich [7]

Answer:

$x=-1,\:x=-7,\:x=i,\:x=-i$

Step-by-step explanation:

Considering the equation

$x^4+8x^3+8x^2+8x+7=0$

Solving

$x^4+8x^3+8x^2+8x+7$

$\mathrm{Factor\:}x^4+8x^3+8x^2+8x+7:\quad \left(x+1\right)\left(x+7\right)\left(x^2+1\right)$

$\mathrm{Use\:the\:rational\:root\:theorem}$

$a_0=7,\:\quad a_n=1$

$\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:7,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1$

$\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:7}{1}$

$-\frac{1}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+1$

$=\left(x+1\right)\frac{x^4+8x^3+8x^2+8x+7}{x+1}...[A]$

Solving

$\frac{x^4+8x^3+8x^2+8x+7}{x+1}$

$=x^3+7x^2+x+7$

Putting $\frac{x^4+8x^3+8x^2+8x+7}{x+1}$ = $x^3+7x^2+x+7$ in equation [A]

So,

$\left(x+1\right)\frac{x^4+8x^3+8x^2+8x+7}{x+1}...[A]$

$=\left(x+1\right)x^3+7x^2+x+7$

$x^3+7x^2+x+7=\left(x+7\right)\left(x^2+1\right)$

So,

Equation [A] becomes

$=\left(x+1\right)\left(x+7\right)\left(x^2+1\right)$

So, the polynomial equation becomes

$\left(x+1\right)\left(x+7\right)\left(x^2+1\right)=0$

$\mathrm{Using\:the\:Zero\:Factor\:Principle:\quad \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$ $\mathrm{Solve\:}\:x+1=0:\quad x=-1$