now, the denominator has a higher degree, a degree of 1, than the numerator's, therefore the horizontal asymptote for this function is at y = 0.
now, the vertical asymptotes of it, are at the zeros of the denominator, namely x = 0, when is x = 0? at 0, so the vertical asymptote for this function is at x = 0, the y-axis.
now, if we want the horizontal asymptote moved over from its position at 0, over to x = 5, simply translate it by 5 units,
.
and if we want the vertical asymptote to move down from 0 to -3, simply translate the function vertically 3 units,
First, let's look at the ones with 0.
(0,16) -> since the x is zero, it would be on the y-axis.
(3,0) -> since the y is zero, it would be on the x-axis.
Now, let me add a picture of the quadrants, so you can see where the points belong.
(2,-12) -> IV
(-1,2) -> II
(36.7, 3.9) -> I
(-5/8, -5 1/3)-> III
I hope this helps!
~cupcake
$720.00
-
-
30×10=300
and
30×14=420
(you multiply the money with the amount of hours they spent working)
300
+ 420
----------
$720
hope this helps you out
Harry is one third as old as his father. If his father is years old, how old is Harry? Answer: x/3+4.
Equation: 1/3(x+12)=x/3+4
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