If the domain and range have the same number is it still a function??

ASAP! find the slope of a line that is perpendicular to y=-1/2x+4

aliya0001 [1]

We know that :

Ф Product of the slopes of two lines perpendicular to each other should be equal to -1

Let the slope of the line perpendicular to given line be : M

Given equation of the line : y = -1/2x + 4

This line is in the form : y = mx + c, where m is the slope and c is the y intercept

Comparing with y = mx + c :

we can notice that slope of the given line is -1/2

⇒ M × -1/2 = -1

⇒ M × 1/2 = 1

⇒ M = 2

Answer : Slope of the line perpendicular to given line is 2

8 0

3 years ago

Căn 84 bình phương trừ 37 bình phương chia 47

BlackZzzverrR [31]

Answer:

$\sqrt{84^{2} } -37^{2} /47$ =257 9/47

Step-by-step explanation:

3 0

3 years ago

Y = e^(7 sqrt(x)) i would like to find composite function of it

monitta

SJKsbijuigiugsuigsiuiug

6 0

4 years ago

An arithmetic sequence has a common difference of 5 and the 3rd term is 15. What is the 5th term?

trapecia [35]

Answer:

an=8n−14

Step-by-step explanation:

for an AP

where

a

1

=

the first term

d

=

the common difference

then we have

a

1

,

(

a

1

+

d

)

,

(

a

1

+

2

d

)

,

...

,

a

1

+

(

n

−

1

)

d

)

,

.

we are given the third term

10

=

a

1

+

2

d

−

(

1

)

and the fifth term

26

=

a

1

+

4

d

−

(

2

)

subtract

(

2

)

−

(

1

)

16

=

2

d

⇒

d

=

8

sub into

(

1

)

10

=

a

1

+

2

×

8

⇒

a

1

=

−

6

so the nth term

a

n

=

a

+

(

n

−

1

)

will be

a

n

=

−

6

+

8

(

n

−

1

)

a

n

=

8

n

−

14

3 0

3 years ago

A rectangle is inscribed in a circle of radius r. If the rectangle is not a square, which of the following could be the perimete

evablogger [386]

Answer:

$2r(\sqrt{3}+1)$

Step-by-step explanation:

A rectangle is inscribed in a circle of radius r.

Radius of the circle is 'r' . the diameter of circle is 2 times radius is 2r

The diameter of the circle becomes the diagonal of the rectangle.

The one part of the rectangle forms a triangle with hypotenuse 2r

Triangle is a special 30:60:90 degree angle

the ratio of the special triangle is $1: \sqrt{3} :2$

Hypotenuse is '2r' , so the ratio becomes

$r: \sqrt{3}r :2r$

So the width of the rectangle is 'r' and length of the rectangle is $\sqrt{3}r$

Perimeter = 2 times length + 2 times width

$perimeter = 2\sqrt{3} r+2r=2r(\sqrt{3}+1)$

7 0

3 years ago