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son4ous [18]
3 years ago
9

sarah is 27 years old and is retiring at the age of 65. when she retires, she estimates that she will need a semiannual income f

or 20 years. if sarah contributes 9% of her semiannual income of $18,567.11 to a 401(k) paying 6.1% compounded semiannually, approximately what semiannual income will she be able to draw?
Mathematics
1 answer:
hichkok12 [17]3 years ago
5 0
<span>In order for you to be able to solve this problem you have to first identify what the questions is asking. In this case it wants to know the approximation of what the semiannual income that Sarah will be able to draw.

To solve this you simply have to find the future value of her investment prior to retirement and use the as her investment amount upon retirement.

<span>I hope it helps, Regards. </span></span>
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Weary of the low turnout in student elections, a college administration decides to choose an SRS of three students to form an ad
-Dominant- [34]

Answer:

P(ABC) = 0.110592

P(ABC^c) = 0.119808

P(AB^cC) = 0.119808

P(A^cBC) = 0.119808

P(AB^cC^c)  = 0.129792

P(A^cBC^c)  = 0.129792

P(A^cB^cC)  = 0.129792

P(A^cB^cC^c)  = 0.140608

Step-by-step explanation:

Given

P(A) = P(B) = P(C) = 48\%

Convert the probability to decimal

P(A) = P(B) = P(C) = 0.48

Solving (a): P(ABC)

This is calculated as:

P(ABC) = P(A) * P(B) * P(C)

This gives:

P(ABC) = 0.48*0.48*0.48

P(ABC) = 0.110592

Solving (b): P(ABC^c)

This is calculated as:

P(ABC^c) = P(A) * P(B) * P(C^c)

In probability:

P(C^c) = 1 - P(C)

So, we have:

P(ABC^c) = P(A) * P(B) * (1 - P(C))

P(ABC^c) = 0.48 * 0.48 * (1 - 0.48)

P(ABC^c) = 0.48 * 0.48 * 0.52

P(ABC^c) = 0.119808

Solving (c): P(AB^cC)

This is calculated as:

P(AB^cC) = P(A) * P(B^c) * P(C)

P(AB^cC) = P(A) * [1 - P(B)] * P(C)

P(AB^cC) = 0.48 * (1 - 0.48)* 0.48

P(AB^cC) = 0.48 * 0.52* 0.48

P(AB^cC) = 0.119808

Solving (d): P(A^cBC)

This is calculated as:

P(A^cBC) = P(A^c) * P(B) * P(C)

P(A^cBC) = [1-P(A)] *P(B) * P(C)

P(A^cBC) = (1 - 0.48)* 0.48 * 0.48

P(A^cBC) = 0.52* 0.48 * 0.48

P(A^cBC) = 0.119808

Solving (e): P(AB^cC^c)

This is calculated as:

P(AB^cC^c)  = P(A) * P(B^c) * P(C^c)

P(AB^cC^c)  = P(A) * [1-P(B)] * [1-P(C)]

P(AB^cC^c)  = 0.48 * [1-0.48] * [1-0.48]

P(AB^cC^c)  = 0.48 * 0.52*0.52

P(AB^cC^c)  = 0.129792

Solving (f): P(A^cBC^c)

This is calculated as:

P(A^cBC^c)   = P(A^c) * P(B) * P(C^c)

P(A^cBC^c)   = [1-P(A)] * P(B) * [1-P(C)]

P(A^cBC^c)   = [1-0.48] * 0.48 * [1-0.48]

P(A^cBC^c)   = 0.52 * 0.48 * 0.52

P(A^cBC^c)  = 0.129792

Solving (g): P(A^cB^cC)

This is calculated as:

P(A^cB^cC)  = P(A^c) * P(B^c) * P(C)

P(A^cB^cC)  = [1-P(A)] * [1-P(B)] * P(C)

P(A^cB^cC)  = [1-0.48] * [1-0.48] * 0.48

P(A^cB^cC)  = 0.52 * 0.52 * 0.48

P(A^cB^cC)  = 0.129792

Solving (h): P(A^cB^cC^c)

This is calculated as:

P(A^cB^cC^c)  = P(A^c) * P(B^c) * P(C^c)

P(A^cB^cC^c)  = [1-P(A)] * [1-P(B)] * [1-P(C)]

P(A^cB^cC^c)  = [1-0.48] * [1-0.48] * [1-0.48]

P(A^cB^cC^c)  = 0.52*0.52*0.52

P(A^cB^cC^c)  = 0.140608

5 0
3 years ago
Evaluate the integral using integration by parts with the indicated choices of u and dv. (Use C for the constant of integration.
Aleksandr-060686 [28]

Take

u=\ln x\implies\mathrm du=\dfrac{\mathrm dx}x

\mathrm dv=4x^2\,\mathrm dx\implies v=\dfrac43x^3

Then

\displaystyle\int4x^2\ln x\,\mathrm dx=\frac43x^3\ln x-\frac43\int x^2\,\mathrm dx=\frac43x^3\ln x-\frac49x^3+C

=\boxed{\dfrac49x^3(3\ln x-1)+C}

5 0
3 years ago
What’s 9/250 simplified?
hjlf
9/250 is in it's simplest form

If you wanted it's decimal form, it is 0.036
8 0
3 years ago
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Find the area A of triangle JKL with the vertices J(5,8), K(0,7), and L(5,4)
eimsori [14]

Answer:

Area of the triangle is 10 square units

Step-by-step explanation:

Recall that the formula for the area of a triangle is: "base x height / 2", and  in this case, we can consider the triangle's base as the segment that joins the vertices (5, 4) and (5, 8) which gives a segment length of 4 units. The height of the triangle is then the distance between the third vertex (0,7) and the base, which is exactly 5 units. Then the area becomes:

Area = 4 x 5 / 2 = 10 square units.

5 0
3 years ago
Help me please hurry
tatuchka [14]

Answer:

61°

this triangle is split in half and forms 2 triangles. These triangles must be congruent since they are each excatly half of this rectangle

Therefore, <2 is going to be equal to the m< the corresponding angle in the other triangle. <2 = 61°

<2 is also equal to 61° by the interior angles theorem

Step-by-step explanation:

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3 years ago
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