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Sonja [21]
3 years ago
12

How would you solve this problem?

Mathematics
1 answer:
Allushta [10]3 years ago
7 0
<h2>Greetings!</h2><h3>To find that these two slopes are the same, you can calculate the gradients of the two lines, which is what all the options are.</h3>

The equation for the gradient is:

\frac{y2 - y1}{x2 - x1}

<h3>Where the differeny y and x values are the two co-ordinates of the lines starting and end point.</h3>

Take the line JL, one of the two sets of coordinates are (-4 , 0) and the other set is (-7, 4)

<h3>If you use these two sets to substitute into the equation for the gradient, you can use either y coordinates in both sets as y1 or y2 as long as this method is throughout and the x value is the same in both sets ( both numbers are x1 and y1, one cannot be x1 and the other y2).</h3>

Lets use ( -4 , 0) and (-7 , 4) which are the coordinates for JL.

y1 = 4 and y2 = 0

0 - 4

<h3>Now lets use the two x values:</h3>

x1 = -7 and x2 = -4

(-4) - (-7)  

<h3>Simply put these two equations in a fraction:</h3>

\frac{0 - 4}{-5 - (-7)}

<h3>Now choose another two sets of values for MP, such as (-10 , 8) and (-1 , -4)</h3>

y1 = 8 and y2 = -4

-4 - 8

<h3>Lets use the two x values:</h3>

x1 = -10 and x2 = -1

-1 - (-10)

<h3>Put them into a fraction:</h3>

\frac{-4 - 8}{-1 - (-10)}

<h3>Now these two fractions can be put together, putting an equal sign in middle because they both are same gradient:</h3>

\frac{0 - 4}{-5 - (-7)} = \frac{-4 - 8}{-1 - (-10)}

<h3>Meaning that your answer if G!</h3>
<h2>Hope this helps!</h2>


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Which binomial is a factor of the quadratic trinomial x2 − 7x + 12? A. (x + 2) B. (x − 6) C. (x + 3) D. (x − 4)
White raven [17]

Answer:

D

Step-by-step explanation:

To factor a quadratic you need to think about what adds up to the b coefficient (the number in front of b) and multiplies to the constant. 3 and 4 do these, but you also know that you have -7 instead of positive 7. A negative times a negative is equal to a positive, which you can do (x-3)(x-4) to equal your quadratic trinomial.

7 0
3 years ago
Evaluate the following expression. 8to the power of 3 − 9 ⋅ 2 ÷ 3 = ?
ahrayia [7]

Answer:

8^-3  I think  (i'm too lazy to simplify)

Step-by-step explanation:

3 - 9 * 2 ÷ 3 = ?

3 - 18 ÷ 3 = ?

3 - 6 = -3

8 to the power of -3

hmmmm i dont think im right tell me if im not

3 0
3 years ago
Andre and Elena are each saving money. Andre starts with $100 in his savings account and adds $5 per week. Elena starts with $10
katovenus [111]

Answer:

Andre has more money in his savings account.

Step-by-step explanation:

We need to have equations for both Andre and Elena. Andre starts with $100 in his savings and adds $5 per week.  Based on this, Andre's equation will be y = 5x + 100. Elena starts with $10 and adds $20 per week. Based on this, Elena's equation will be y = 20x + 10.

Andre: y = 5x + 100

Elena: y = 20x + 10

We have to figure out who will have more money in their account after 4 weeks. To do that, we plug in 4 into x because x is the number of weeks.

Andre: y = 5(4) + 100

           y = 20 + 100

           y = 120

Andre has $120 after 4 weeks.

Elena: y = 20(4) + 10

          y = 80 + 10

          y = 90

Elena has $90 after 4 weeks.

Which is greater? $120 or $90? That's right, its $120. Andre has more money in his savings account. I hope this helps!  

7 0
3 years ago
Given that the circumference of an orange us 50.24mm find the volume of the orange
amid [387]

Answer: 803mm

Step-by-step explanation:

7 0
3 years ago
A circle with radius of \greenD{3\,\text{cm}}3cmstart color #1fab54, 3, start text, c, m, end text, end color #1fab54 sits insid
Zolol [24]

Answer:

The area of the shaded region is 125.664 square centimetre

Step-by-step explanation:

Area of the shaded region  =  area of the circle with radius 7 cm - area of the circle with  radius 3 cm----------------(1)

<u>Step 1:  Finding the area of the circle with radius 7 cm</u>

Area of the circle A = \pi r^2

On substituting the value of the radius, we get

Area of the circle A =\pi(7)^2

Area of the circle A = 49 \pi square centimetre----------------(2)

<u>Step 2:  Finding the area of the circle with radius 3 cm</u>

Area of the circle a = \pi r^2

On substituting the value of the radius, we get

Area of the circle a  = \pi (3)^2

Area of the circle a  = 9 \pi square centimetre ----------------(3)

<u>Step 3:  Finding the area of the shaded region</u>

Area of the shaded region  = 49 \pi - 9\pi

= 40 \pi

= 125.664 square centimetre

6 0
3 years ago
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