Answer: The length of the path = 157 inches { approx}
Step-by-step explanation:
Given: The length of the path = 4 meters
1 meter = 100 centimeters
So 4 meters = 400 centimeters
Also 1 in. ≈ 2.54 cm
Now, 
![=157.480314961\approx 157 \ \ \ \ \ \text{ [Rounded to the nearest inch.]}](https://tex.z-dn.net/?f=%3D157.480314961%5Capprox%20157%20%20%5C%20%5C%20%5C%20%5C%20%5C%20%5Ctext%7B%20%5BRounded%20to%20the%20nearest%20inch.%5D%7D)
Hence, the length of the path = 157 inches { approx}
Answer:
150
Step-by-step explanation:
Answer:
35cm
Step-by-step explanation:
Given data
Length= 21cm
Width= 28cm
Diagonal= ???
Applying Pythagoras theorem
D^2= L^2+W^2
D^2= 21^2+28^2
D^2= 441+784
D^2= 1225
D= √1225
D= 35cm
Hence the diagonal is 35cm
Answer:
Answer:
85
Step-by-step explanation:
64+16+4+1= 85 is the total distance i believe
