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ASHA 777 [7]
2 years ago
15

Help please?? What do I put for the last 2??

Mathematics
2 answers:
bija089 [108]2 years ago
7 0

Answer:

I Didnt mean to answer sorry i cant help

I dont know

How Go back Srry Again

GenaCL600 [577]2 years ago
7 0
Answer: 4(5j+3j) = 32j and 4(3j) = 12j

explanation: you have to distribute the 4 into both of the problems. when you do this for the first one you get (20j+12j) and that just adds up to 32j. when you do this for the second one you get 12j
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A car seller buys a car from a manufacturer for 10,000. He increases the cost by 5 percent. What is the markup amount?
Ksenya-84 [330]
The seller marks up the price by $500, for a grand total of $10,500
7 0
2 years ago
9-c=-13.help......algebra
Ksivusya [100]
9 - c = -13
-c = -13 - 9
-c = - 22
c = 22 <===
3 0
3 years ago
The taxi and takeoff time for commercial jets is a random variable x with a mean of 8.3 minutes and a standard deviation of 3.3
In-s [12.5K]

Answer:

a) There is a 74.22% probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

b) There is a 1-0.0548 = 0.9452 = 94.52% probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes.

c) There is a 68.74% probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

The taxi and takeoff time for commercial jets is a random variable x with a mean of 8.3 minutes and a standard deviation of 3.3 minutes. This means that \mu = 8.3, \sigma = 3.3.

(a) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes?

We are working with a sample mean of 37 jets. So we have that:

s = \frac{3.3}{\sqrt{37}} = 0.5425

Total time of 320 minutes for 37 jets, so

X = \frac{320}{37} = 8.65

This probability is the pvalue of Z when X = 8.65. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{8.65 - 8.3}{0.5425}

Z = 0.65

Z = 0.65 has a pvalue of 0.7422. This means that there is a 74.22% probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

(b) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes?

Total time of 275 minutes for 37 jets, so

X = \frac{275}{37} = 7.43

This probability is subtracted by the pvalue of Z when X = 7.43

Z = \frac{X - \mu}{\sigma}

Z = \frac{7.43 - 8.3}{0.5425}

Z = -1.60

Z = -1.60 has a pvalue of 0.0548.

There is a 1-0.0548 = 0.9452 = 94.52% probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes.

(c) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes?

Total time of 320 minutes for 37 jets, so

X = \frac{320}{37} = 8.65

Total time of 275 minutes for 37 jets, so

X = \frac{275}{37} = 7.43

This probability is the pvalue of Z when X = 8.65 subtracted by the pvalue of Z when X = 7.43.

So:

From a), we have that for X = 8.65, we have Z = 0.65, that has a pvalue of 0.7422.

From b), we have that for X = 7.43, we have Z = -1.60, that has a pvalue of 0.0548.

So there is a 0.7422 - 0.0548 = 0.6874 = 68.74% probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes.

7 0
3 years ago
A circle has been dissected into 16 congruent sectors. The base of one sector is 1.17 units, and its height is 2.94 units. Using
worty [1.4K]

Answer:

The approximate area of the circle is 27.5184∧2

Step-by-step explanation:

In order to calculate the approximate area of the circle we would have to calculate the following formula:

approximate area of the circle=approximate area of one triangle*number of congruent sectors

number of congruent sectors=16

approximate area of one triangle=1/2*base*height

base=1.17 units

height=2.94 units

Therefore, approximate area of one triangle=1/2*1.17*2.94

approximate area of one triangle=1.7199 units∧2

Therefore, approximate area of the circle=1.7199 units∧2*16

approximate area of the circle=27.5184∧2

7 0
3 years ago
Help please. and thank you
Dominik [7]
Every Triangle adds up to 180 degrees

180 - 63 = 117 | 117 - 56 = 61 so x = 61

12y + 3 = 51 so y = 4
8 0
3 years ago
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