Answer:
62: 300l/hr
63: .018mi/s
64: .46qt/s
65: 298.2mi/hr
Step-by-step explanation:
62: 5x60=300
63: 68/60=1.13/60=.018
64:7gal=28qt 28/60=.467
65: 8km=4.97mi 4.97x60=298.2
Answer:Coplanar line
Step-by-step explanation:
Answer:
9:19
Step-by-step explanation:
Total number of students = 28
Number of boys = 19
Number of girls = Total number of students - Number of boys = 28-19 = 9
Therefore, ratio of girls to boys = Number of girls/Number of boys = 9/19 = 9:19
Explanation:
A sequence is a list of numbers.
A <em>geometric</em> sequence is a list of numbers such that the ratio of each number to the one before it is the same. The common ratio can be any non-zero value.
<u>Examples</u>
- 1, 2, 4, 8, ... common ratio is 2
- 27, 9, 3, 1, ... common ratio is 1/3
- 6, -24, 96, -384, ... common ratio is -4
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<u>General Term</u>
Terms of a sequence are numbered starting with 1. We sometimes use the symbol a(n) or an to refer to the n-th term. The general term of a geometric sequence, a(n), can be described by the formula ...
a(n) = a(1)×r^(n-1) . . . . . n-th term of a geometric sequence
where a(1) is the first term, and r is the common ratio. The above example sequences have the formulas ...
- a(n) = 2^(n -1)
- a(n) = 27×(1/3)^(n -1)
- a(n) = 6×(-4)^(n -1)
You can see that these formulas are exponential in nature.
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<u>Sum of Terms</u>
Another useful formula for geometric sequences is the formula for the sum of n terms.
S(n) = a(1)×(r^n -1)/(r -1) . . . . . sum of n terms of a geometric sequence
When |r| < 1, the sum converges as n approaches infinity. The infinite sum is ...
S = a(1)/(1-r)
There are 7 sides available.
The fundamental counting principal tells us to find the total number of combinations of independent items, multiply the number of choices from each one (choices x choices x....)
This means that drink x sides x sandwiches = 560. We know there are 16 sandwiches and 5 drinks. Let S be the number of sides:
15(6)(S) = 560
80S = 560
Divide both sides by 80:
80S = 560/80
S = 7
