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kenny6666 [7]
3 years ago
14

10 points Can someone please do number 4

Mathematics
1 answer:
Andrei [34K]3 years ago
3 0

This question wants to know the domain.  For example: (2,4) 2 is the domain and 4 is the range.

Then, they want you to solve by finding X the range when x =-1

x-4/x^2+5x-36

Put -1 everytime you see x

-1-4/-1^2+5(-1)-36

-5/1+(-6)-36

-5/-41 This is the range.

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1. Marciano draws five cards from a 52-card deck. Calculate the probability of each given event. a. Two cards are sevens, given
OverLord2011 [107]

Step-by-step explanation:

In a standard deck of 52 cards, face cards are cards with faces on them. There are 12 of them, 3 in each suit. They are also called “court cards,” because they show Kings, Queens and Jacks.” An Ace cannot be considered a “face card,” for the simple reason that it has no face on it.

a) Two cards are sevens, given there are no face cards

 = ( 52- 12 face cards = 40)

 =  ( 4÷40×3÷40 = 0.1×0.075 = 0.0075 ( or) 0.75%

 =  ( 4÷40×3÷40 = 0.1×0.075 = 0.0075 ( or) 0.75%

b. There is exactly one face card, given three of the cards are red

Total cards=  (52-11 =41 cards)

assumed that the exactly one face card is not a red card

Red cards = (26-6 red face cards = 20 cards )

Picking Three red cards

=(20÷41 ×19÷40×18÷39 =0.487 ×0.475 ×0.461 =0.107 or 11%

=(20÷41 ×19÷40×18÷39 =0.487 ×0.475 ×0.461 =0.107 or 11%

c. Three cards are Aces, given one of the Aces was removed from the deck

Total cards = (52-1 ace card = 51 cards)

Picking three cards are ace

= (3÷51 ×2÷50×1÷49 = 0.059×0.04×0.02 = 0.0000472

= (3÷51 ×2÷50×1÷49 = 0.059×0.04×0.02 = 0.0000472

5 0
3 years ago
Solve the proportion <br> 2/z-5=z/0.5zpower2+7<br> A.1/5<br> B.6<br> C.-7/5<br> D.-14/5
stiv31 [10]
2 / (z-5) = z / (0.5z^2 + 7)
cross multiply
z(z - 5) = 2(0.5z^2 + 7) =
z^2 - 5z = z^2 + 14 = 
z^2 - z^2 - 5z = 14
-5z = 14
z = -14/5
5 0
3 years ago
Suppose you take a 30-question, multiple-choice test, in which each question contains 4 choices: A, B, C, and D. If you randomly
mina [271]

Answer:

(a) The probability you pass the exam is 0.0000501.

(b) The expected number of correct guesses is 7.5.

(c) The standard deviation is 2.372.

Step-by-step explanation:

We are given that you take a 30-question, multiple-choice test, in which each question contains 4 choices: A, B, C, and D. And you randomly guess on all 30 questions.

Since there is an assumption of only 1 correct choice out of 4 which means the above situation can be represented through binomial distribution;

P(X =x) = \binom{n}{r}\times p^{r}\times (1-p)^{n-r}  ; x = 0,1,2,3,......

where, n = number of trials (samples) taken = 30

           r = number of success = at least 60%

           p = probbaility of success which in our question is the probability

                 of a correct answer, i.e; p = \frac{1}{4} = 0.25

Let X = Number of questions that are correct

So, X ~ Binom(n = 30 , p = 0.25)

(a) The probability you pass the exam is given by = P(X \geq 18)

Because 60% of 30 = 18

P(X \geq 18) = P(X = 18) + P(X = 19) +...........+ P(X = 29) + P(X = 30)

= \binom{30}{18}\times 0.25^{18}\times (1-0.25)^{30-18} + \binom{30}{19}\times 0.25^{19}\times (1-0.25)^{30-19} +.......+ \binom{30}{29}\times 0.25^{29}\times (1-0.25)^{30-29} + \binom{30}{30}\times 0.25^{30}\times (1-0.25)^{30-30}

= 0.0000501

(b) The expected number of correct guesses is given by;

  Mean of the binomial distribution, E(X) =  n \times p

                                                                =  30 \times 0.25 = 7.5

(c) The standard deviation of the binomial distribution is given by;

      S.D.(X)  =  \sqrt{n \times p \times (1-p)}

                    =  \sqrt{30 \times 0.25 \times (1-0.25)}

                    =  \sqrt{5.625}  =  2.372                

8 0
4 years ago
What is the multiplicity of each of the roots of the graph of f(x)=−-x^3+2x^2+3x?
DerKrebs [107]

Answer:

A. -1, multiplicity 1; 0, multiplicity 1; 3, multiplicity 1.

Step-by-step explanation:

Let f(x) = -x^{3}+2\cdot x^{2} + 3\cdot x, to determine its roots and multiplicities we proceed to factorize the polynomial:

1) -x^{3}+2\cdot x^{2} +3\cdot x Given

2) x\cdot (-x^{2}+2\cdot x + 3) Distributive property

3) x\cdot (x-3)\cdot (x+1) Quadratic formula/Result

The roots and multiplicities of f(x) = -x^{3}+2\cdot x^{2} + 3\cdot x are:

<em>0 (multiplicity 1)</em>

<em>3 (multiplicity 1)</em>

<em>-1 (multiplicity 1)</em>

Therefore, the correct answer is A.

4 0
3 years ago
Read 2 more answers
First to answer gets brainlest &lt;33
Crazy boy [7]
Awww man the other person answered before me :(
7 0
3 years ago
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