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lakkis [162]
3 years ago
6

Find the 5th term of the sequence which has a first term of 17 and has a common ratio of 3.1.

Mathematics
2 answers:
Murrr4er [49]3 years ago
5 0
The 1st term of the sequence:
a 1 = 17
r = 3.1
a n = a 1 * r^(n-1)
a 5 = a 1 * r^4
a 5 = 17 * 3.1^(4) = 17 * 92.3521
Answer:
a 5 = 1,569.9857
dsp733 years ago
5 0
Our n will be 5-1 =4

and with the first term of 17 with the common ration of 3.1 our 5th sequence term will be 
17(3.1^4) = 1570
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The complete question is as follows.

The equation a = \frac{1}{2}(b_1 + b_2 )h can be used to determine the area , <em>a</em>, of a trapezoid with height , h, and base lengths, b_1 and b_2. Which are equivalent equations?

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Step-by-step explanation: To determine b_1:

a = \frac{1}{2}(b_1 + b_2 )h

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a = \frac{1}{2}(b_1 + b_2 )h

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\frac{2a}{h} - b_1 = b_2

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