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Vitek1552 [10]
3 years ago
10

Let f(x) = 3x + x², find f(4).

Mathematics
2 answers:
xenn [34]3 years ago
4 0
F(4) is equivalent to 28 because when you plug in 4 for the x, you get 28.
ArbitrLikvidat [17]3 years ago
4 0

Answer:

f(4)=28

Step-by-step explanation:

Let f(x) = 3x + x², find f(4).

f(x) is a function such that the value of x at any time gives the value of 3x + x².

So when we are given the value of f(x), we just input the value of x in the equation and solve. Assuming were looking for f(0),

f(0) = 3×0 + 0²= 0

From the question given

Let f(x) = 3x + x², find f(4)

we would put x=4 in 3x + x²

This would give 3×4 + 4²=12+16=28

So f(4) = 3×4 + 4²=12+16=28

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There are 158 students registered for American History classes. There are twice as many students registered in second period as
Margarita [4]

There are 28 students in first period and 56 students in sceond period and 74 students in third period

<em><u>Solution:</u></em>

Let the number of students in first period be "x"

Let the number of students in second period be "y"

Let the number of students in third period be "z"

<em><u>There are 158 students registered for American History classes.</u></em>

Therefore,

x + y + z = 158 ---------- eqn 1

<em><u>There are twice as many students registered in second period as first period</u></em>

number of students in second period = twice of number of students in first period

y = 2x ------- eqn 2

<em><u>There are 10 less than three times as many students in third period as in first period</u></em>

number of students in third period = 3 times number of students in first period - 10

z = 3x - 10 ------ eqn 3

<em><u>Substitute eqn 2 and eqn 3 in eqn 1</u></em>

x + 2x + 3x - 10 = 158

6x = 168

<h3>x = 28</h3>

<em><u>Substitute x = 28 in eqn 2</u></em>

y = 2(28)

<h3>y = 56</h3>

<em><u>Substitute x = 28 in eqn 3</u></em>

z = 3(28) - 10

z = 84 - 10

<h3>z = 74</h3>

Thus there are 28 students in first period and 56 students in sceond period and 74 students in third period

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