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2 years ago

13

You spend 2 hours and 15 minutes commuting to work each day. You work five days per week. How much time do you spend commuting t

o work each week?

1 answer:

Sonbull [250]2 years ago

8 0

1075 minutes commuting to work every day.

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Consider this equation.

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Answer:

I know u saw me before but the answer is B hope it helps! =)

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2 years ago

Can anyone answer these problems?

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I can answer these problems

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3 years ago

An apple farmer is deciding how to use each day's harvest. She can use the harvest to produce apple cider or apple juice for the

Andreas93 [3]

Answer:For this item, we let x and y be the number of bushels of apple that will be used to produce apple cider and apple juice, respectively. The situation above is best represented by the following equations,

x + y = 18

20x + 15y = 330

The values of x and y from the equations above are 12 and 6, respectively. Therefore, 12 bushels will be used to make apple cider and 6 bushels will be used to make apple juice.

Step-by-step explanation:

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3 years ago

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A tuxedo rental service charges a $150 flat fee for a suit plus $50 per additional day. Write and solve an equation to determine

V125BC [204]

Answer:

150+50*4=350

Step-by-step explanation:

hope it helped sorry if it's not what you wanted.

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3 years ago

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A spinner numbered 1 through 12 is spun. Find the probability that

anastassius [24]

Answer:

$\dfrac{1}{6}$

Step-by-step explanation:

Let <em>A</em> be the event of getting an odd number.

<em>P(A)</em> be the probability of getting an odd number.

Total odd numbers here are 6 i.e. $\{1,3,5,7,9,11\}$

Here, total numbers in the game are 12 i.e $\{1,2,3,....,12\}$ .

Formula for probability of an <em>event E</em> can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

$P(A) = \dfrac{6}{12}\\\Rightarrow \dfrac{1}{2}$

Let <em>B</em> be the event of getting 11.

<em>P(B)</em> be the probability of getting 11.

Total number of possible cases is 1.

$P(B) = \dfrac{1}{12}$

$P(A \cap B)$ is the probability that we get 11 and an odd number.

Possible number of cases = 1

$P(A\cap B) = \dfrac{1}{12}$

<em>P(B/A)</em> is the probability that we get an 11 given that it is an odd number.

$P(B/A) = \dfrac{P(A \cap B)}{P(A)}\\\Rightarrow \dfrac{\dfrac{1}{12}}{\dfrac{1}{2}}\\\Rightarrow \dfrac{1}{6}$

Hence, P(B/A) = $\dfrac{1}{6}$

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3 years ago

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