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Sonja [21]
3 years ago
5

What are the measures of ∠1 and ∠2? PLEASE ANSWER

Mathematics
1 answer:
Tcecarenko [31]3 years ago
7 0

9514 1404 393

Answer:

  (b)  m∠1 = 67.4°, m∠2 = 104.5°

Step-by-step explanation:

It is easiest to find angle 2 first, then make your answer selection based on that.

The exterior angle 121.8° is the sum of the remote interior angles 17.3° and angle 2. Then ...

  angle 2 = 121.8° -17.3° = 104.5° . . . . . . . matches the second choice

__

Angle 2 is an exterior angle of the top triangle. It, too, is the sum of the remote interior angles:

  104.5° = angle 1 + 37.1°

  angle 1 = 104.5° -37.1° = 67.4°

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Jay factored the 4 term polynomial : x^3 - 9x +2x^2 - 18 and decided that the complete factorization was : ( x + 2 ) (x^2-9 ). B
labwork [276]

Answer:

x^3-9x+2x^2-18\left(x+2\right)\left(x+3\right)\left(x-3\right)

Step-by-step explanation:

we are given that x^3-9x+2x^2-18

w are sked to step by step factorise the above polynomial

\left(x^3+2x^2\right)+\left(-9x-18\right)

-9\mathrm{\:from\:}-9x-18\mathrm{:\quad }-9\left(x+2\right)

-9x-9\cdot \:2

-9\left(x+2\right)

\mathrm{Factor\:out\:}x^2\mathrm{\:from\:}x^3+2x^2\mathrm{:\quad }x^2\left(x+2\right)

-9\left(x+2\right)+x^2\left(x+2\right)

\left(x+2\right)\left(x^2-9\right)

x^2-9:\quad \left(x+3\right)\left(x-3\right)

x^2-9

\mathrm{Rewrite\:}9\mathrm{\:as\:}3^2

=x^2-3^2

\mathrm{Apply\:Difference\:of\:Two\:Squares\:Formula:\:}x^2-y^2=\left(x+y\right)\left(x-y\right)

x^2-3^2=\left(x+3\right)\left(x-3\right)

Hence

x^3-9x+2x^2-18=\left(x+2\right)\left(x+3\right)\left(x-3\right)

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