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3 years ago

7) 6x + 16 + = 2x + 28

Mathematics

2 answers:

Ede4ka [16]3 years ago

7 0

Answer: the answer to number seven is x=3

Step-by-step explanation:

Tanya [424]3 years ago

5 0

Answer:

sorry

Step-by-step explanation:

im apologizing duh.

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What is the value of x?

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Answer: 5

Step-by-step explanation:

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1 year ago

Which expression is a trinomial? 2x² + 2x - 4 7x^3 - 2X 50x 2x²

andreev551 [17]

The first option: 2x^2+2x-4 since there are three terms

5 0

2 years ago

Read 2 more answers

What is the positive solution to the equation 0 = 3x2-31 ?

Bas_tet [7]

Answer:

4.47

Step-by-step explanation:

3x²+31=91

3x²=91-31

3x²=60

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x²=20

x=√20

x=4.47

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2 years ago

EXPERTS/ACE/TRUSTED HELPERS helpppp meeeeeeeee plzzzz

Basile [38]

the 3rd answer should be the correct one

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3 years ago

((81x^3 y^(-1/3))^1/4)/(x^2 y)^1/4 simplify

malfutka [58]

$\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}
\\\\\\
\left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}}\\\\
-------------------------------\\\\$

$\bf \cfrac{\left( 81x^3y^{-\frac{1}{3}} \right)^{\frac{1}{4}}}{(x^2y)^{\frac{1}{4}}}\implies \cfrac{81^{\frac{1}{4}}x^{3\cdot {\frac{1}{4}}}y^{-\frac{1}{3}\cdot {\frac{1}{4}}}}{x^{2\cdot {\frac{1}{4}}}y^{\frac{1}{4}}}\implies
\cfrac{81^{\frac{1}{4}}x^{\frac{3}{4}}y^{-\frac{1}{12}}}{x^{\frac{2}{4}} y^{\frac{1}{4}}}$

$\bf \cfrac{81^{\frac{1}{4}}x^{\frac{3}{4}}x^{-\frac{2}{4}}}{ y^{\frac{1}{4}}y^{\frac{1}{12}}}\implies \cfrac{(3^4)^{\frac{1}{4}}x^{\frac{3}{4}-\frac{2}{4}}}{y^{\frac{1}{4}+\frac{1}{12}}}\implies \cfrac{3^{4\cdot \frac{1}{4}}x^{\frac{1}{4}}}{y^{\frac{4}{12}}}\implies \cfrac{3^{\frac{4}{4}}x^{\frac{1}{4}}}{y^{\frac{1}{3}}}
\\\\\\
\cfrac{3\sqrt[4]{x}}{\sqrt[3]{y}}$

7 0

2 years ago