Find the vertex of the graph of the function. f(x) = (x + 6)^2 + 3

2 answers:

7 0

$\bf ~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ f(x) = (x+6)^2+3\implies f(x) = [x-(\stackrel{h}{-6})]^2\stackrel{k}{+3}~\hfill \stackrel{vertex}{(-6~~,~~3)}$

Oksi-84 [34.3K]3 years ago

6 0

Answer:

(-6,3)

Step-by-step explanation:

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below are the graphs