Answer:
Now we just take square root on both sides of the interval and we got:
And the best option would be:
A. 2.2 < σ < 2.8
Step-by-step explanation:
Information provided
represent the sample mean
population mean
s=2.4 represent the sample standard deviation
n=83 represent the sample size
Confidence interval
The confidence interval for the population variance is given by the following formula:
The degrees of freedom are given by:
The Confidence is given by 0.90 or 90%, the value of 
and 
, the critical values for this case are:
And replacing into the formula for the interval we got:
Now we just take square root on both sides of the interval and we got:
And the best option would be:
A. 2.2 < σ < 2.8
she has 1/4 of a chance of drawing a blue marble
I'll do a similar problem, and I challenge you to do this on your own using similar methods!
x+5y+2z=23
8x+4y+3z=12
9x-3y-7z=-10
Multiplying the first equation by -8 and adding it to the second one (to get rid of the x) and also multiplying the first equation by -9 and adding the third one to get rid of the x there too, we end up with
-36y-13z=-92
and
-48y-25z=-217
Multiplying both equations by -1, we get
36y+13z=-92
48y+25z=217
Multiplying the (new) first equation by -4/3 and adding it to the second (to get rid of the y), we get
(7+2/3)z=94+1/3
Dividing both sides by (7+2/3) to separate the z, we get
z=
Plugging that into
48y+25z=217, we can subtract 25z from both sides and divide by 48 to get
Lastly, we plug this into x+5y+2z=23 to get
x=23-5y-2z by subtracting 5y+2z from both sides to get
Good luck, and feel free to ask with any questions!
Answer:
1.y=3x+1
2.y=1/3x+2
3.y=-2x+5
4.y=4x
5.y=4x-4
6.y=-2x-5
Step-by-step explanation:
(i)
y=mx+c
10=(m)3+1
10=3m+1
10-1=3m
m =3
y=3x+1
And so on...
Answer:
The squared form is not a correct form of the quadratic function.
Step-by-step explanation:
Given some forms of quadratic equation. we have to choose the form which is not correct of the quadratic equation.
As the general form and the standard form of quadratic equation is
where a,b and c are constant.
Also, the vertex form is
where (a,b) is vertex.
Only the three forms of quadratic equation exist. No other form like squared form exist.
Hence, the squared form is not a correct form of the quadratic function.
