Question

Please answer this Calculus 1 question I really need help will give Braniliest five stars!

Answer 1

Answer:

Step-by-step explanation:

Let's first subtitute $e^{7xcosx}$ with $g(x)$

This will turn the problem into

$y = e^{g(x)}$

Using the chain rule, we will find that the derivative of this function, $y'$, is represented by the following:

$y' = g'(x)e^{g(x)}$

We know what $g(x)$ is in this case, but we need to find $g'(x)$.

This can be done with the product rule:

$g'(x) = 7cos(x) - 7xsin(x)$

Plugging these functions back into the original subtitution will give you the final answer:

$y' = (7cos(x) - 7xsin(x))e^{7xcosx}$