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morpeh [17]
3 years ago
8

(x + y + 2)(y + 1) solve

Mathematics
1 answer:
aivan3 [116]3 years ago
3 0

(X + y + 2)(y+1)

xy + y^2 + x + 3y +2

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Which of the following polynomials is in standard form?
arsen [322]
A........................
5 0
3 years ago
Represent the set of numbers as decimals on the number line {5 3/10, 5 1/10, 5 and if you answer more than needed thank you
Alina [70]

Answer:

(0.53 > 0.51) both less than 1 while 5 is greater than both

Step-by-step explanation:

\frac{53}{10} = .53, \frac{51}{10} = .51. and 5

the number line has two sides, with the left side for negative numbers while the right side is for positive numbers.

             <u>                                                                                 </u>

              -5  -4  -3  -2  -1  -.53  -.51   0  .51 .53  1  2  3  4  5            

By studying the number line above all decimal numbers greater than 0 but less than 1 are from 0, .1, .2,.........,.98, .99, 1.00 which is also the same as 1 because all numbers greater than 1 has an invisible point at its right side like 2., 3. which also means 2, 3 while negative number are all less than 0

7 0
3 years ago
What is the product of -1 3/8 and 2 4/5?
kati45 [8]
-1 3/8 and 2 4/5
-1 15/40 and 2 32/40
1 17/40
I hope that helps you!
7 0
4 years ago
Solve: 2cos(x)-square root 3=0 for 0 less than x less than 2 pi
Leona [35]

Answer:

The general solution of   cos x = cos(\frac{\pi }{6})   is  

                                                x = 2nπ±\frac{\pi }{6}

The general solution values  

                                 x = - \frac{\pi }{6}  and x = \frac{\pi }{6}

Step-by-step explanation:

Explanation:-

Given equation is  

                              2cosx-\sqrt{3} =0  for 0

                              2cosx =\sqrt{3}

Dividing '2' on both sides, we get

                             cos x =\frac{\sqrt{3} }{2}

                             cos x = cos(\frac{\pi }{6})

<em>General solution of cos θ = cos ∝ is θ = 2nπ±∝</em>

<em>Now The general solution of   </em>cos x = cos(\frac{\pi }{6})<em>   is  </em>

<em>                                                 x = 2nπ±</em>\frac{\pi }{6}<em></em>

put n=0

x = - \frac{\pi }{6}  and x = \frac{\pi }{6}

Put n=1  

x = 2\pi +\frac{\pi }{6} = \frac{13\pi }{6}

x = 2\pi -\frac{\pi }{6} = \frac{11\pi }{6}

put n=2

x = 4\pi +\frac{\pi }{6} = \frac{25\pi }{6}

x = 4\pi -\frac{\pi }{6} = \frac{23\pi }{6}

And so on

But given 0 < x< 2π

The general solution values  

                                 x = - \frac{\pi }{6}  and x = \frac{\pi }{6}

                               

6 0
3 years ago
3. What is the radius of a circle whose area is 64π cm squared?
nataly862011 [7]

Answer:

Area = 64π

Area \: = \pi {r}^{2}Area=πr

2

64 \: \pi \: = \pi {r}^{2}64π=πr

2

{r}^{2} = \dfrac{64\pi}{\pi}r

2

=

π

64π

{r}^{2} = 64r

2

=64

r \: = \: \sqrt{64} = 8r=

64

=8

Radius = 8 units

Finding the Diameter -

Diameter = Radius x 2 = 8 x 2 = 16 .

\bold{Diameter \: is \: 16 \: units}Diameteris16units

8 0
3 years ago
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