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Elena L [17]
4 years ago
5

What numbers are divisible by two and three

Mathematics
2 answers:
N76 [4]4 years ago
6 0

Answer: 6


Step-by-step explanation: 6 divided by 3 =2

                                             6 divided by 2=3



ElenaW [278]4 years ago
3 0

Answer:

2, 3, 6, 9 only.  

lets take this for an example 126 is divisible by 2 and 6, bc the last number or digit is even obviously, and 2 + 1 + 6 = 9 (3 is a multiple of 9) and so the number is divisible 9. and since this is divisible by 2 and 3 it can also be divisible by 6.

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Nuetrik [128]

Answer:

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Step-by-step explanation:

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7 0
4 years ago
The quotient of y and 27
valina [46]
Quotient means to Divide so we are gonna divide y and 7.
The Answer is Y/7.
5 0
3 years ago
LaTeX: \sqrt[]{36} 36 2) LaTeX: \sqrt[3]{-8} − 8 3 3) LaTeX: -\sqrt[]{100} − 100 4) LaTeX: \sqrt[3]{27} I'm sorry that's the bes
Mamont248 [21]

Given:

Consider the expression are

1) \sqrt{36}

2) \sqrt[3]{-8}

3) -\sqrt{100}

4) \sqrt[3]{27}

To find:

The simplified form of each expression.

Solution:

1. We have,

\sqrt{36}=\sqrt{6^2}

\sqrt{36}=6

Therefore, the value of this expression is 6.

2. We have,

\sqrt[3]{-8}=(-8)^{\frac{1}{3}}

\sqrt[3]{-8}=((-2)^3)^{\frac{1}{3}}

\sqrt[3]{-8}=(-2)^{\frac{3}{3}}

\sqrt[3]{-8}=-2

Therefore, the value of this expression is -2.

3. We have,

-\sqrt{100}=-\sqrt{10^2}

-\sqrt{100}=-10

Therefore, the value of this expression is -10.

4. We have,

\sqrt[3]{27}=(27)^{\frac{1}{3}}

\sqrt[3]{27}=(3^3)^{\frac{1}{3}}

\sqrt[3]{27}=(3)^{\frac{3}{3}}

\sqrt[3]{27}=3

Therefore, the value of this expression is 3.

3 0
4 years ago
Can anyone help me with this
Nataliya [291]
To find surface area, we can use the equation:

SA=2lw+2wh+2lh, where:
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h=7 in

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SA=60+42+140
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3 years ago
Combine the like terms to create an equivalent expression:<br> -3r- 6+ (-1)
Norma-Jean [14]

Answer:

-3r+5 is that answer hdj

7 0
3 years ago
Read 2 more answers
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