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elena-14-01-66 [18.8K]
3 years ago
12

The Average Speed of the orbiting space shuttle is

Chemistry
1 answer:
maxonik [38]3 years ago
8 0

Explanation:

It is given that, the Average Speed of the orbiting space shuttle is  17500 miles/hour.

We need to convert the speed in kilometers/ second

We know that,

1 mile = 1.609 km

or

1 km = 0.621 miles

1 hour = 3600 seconds

17500\ \dfrac{\text{miles}}{\text{hour}}=17500\ \dfrac{\text{miles}}{\text{h}}\times \dfrac{1\ h}{3600\ s}\\\\=17500\times \dfrac{\text{miles}}{3600\ s}

Now cancel the miles in numerator.

17500\times \dfrac{\text{miles}}{3600\ s}=17500\times \dfrac{\text{miles}}{3600\ s}\times \dfrac{1.609\ km}{1\ \text{miles}}\\\\=17500\times \dfrac{1.609}{3600}\ km/s\\\\=7.82\ km/s

So, 17500 miles/hour is equal to 7.82 km/s.

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Answer:

The answer is given below

Explanation:

When electronegativity difference arises between the bonded atoms, then a molecule is polar.

When electros are shared equally between the bonded atoms or when the polar bonds in a bigger molecule cancels out each other, then a a molucule is non polar.

(a) 50% isopropanol/H2O,--- 2 (second least polar)

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(d) 70% isopropanol/H2O. 1 (least polar)

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Which equation represents a chemical equilibrium? * 10 points NH₃(l) ⇌ NH₃(g) N₂(l) ⇌ N₂(g) 2NO₂(g) ⇌ N₂O₄(g) CO₂(s) ⇌CO₂(g)
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A sample of oxygen gas in one container has a volume of 20.0mililiter at 297 K and 101.3 kPa. The entire sample is transferred t
VashaNatasha [74]

Answer: V_2=\frac{101.3kPa\times 20.0ml\times 283K}{297K\times 94.6kPa}

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,:

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

V_2=\frac{P_1V_1T_2}{T_1P_2}

where,

P_1 = initial pressure of gas = 101.3 kPa

P_2 = final pressure of gas = 94.6 kPa

V_1 = initial volume of gas = 20.0 ml

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 297K

T_2 = final temperature of gas = 283K

Now put all the given values in the above equation, we get the final volume of gas.

V_2=\frac{101.3kPa\times 20.0ml\times 283K}{297K\times 94.6kPa}

V_2=20.4ml

Thus the correct numerical setup for calculating the new volume is \frac{101.3kPa\times 20.0ml\times 283K}{297K\times 94.6kPa}

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