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Grace [21]
3 years ago
8

Which statement about oxidation and reduction in a voltaic cell is true? Both oxidation and reduction occur at the anode.

Chemistry
1 answer:
Simora [160]3 years ago
3 0
I believe the correct answer would be that oxidation occurs at the anode and reduction occurs at the cathode. A voltaic cell uses chemical reaction in order to produce electrical energy. It is in the anode that the oxidation reaction happens while in the cathode reduction happens.
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If an element has an atomic number of 20 and a mass number of 41, what is the :
iVinArrow [24]

Answer:

20 protons, 20 electrons, and 21 neutrons

Explanation:

The atomic number of an atom is the number of protons it has. If the atomic number is 20 then we know the atom has 20 protons.

•The mass number of an atom is the total number of protons and neutrons the atom contains. The mass number is 41 and the number of protons is 20, just subtract 20 from 41 and you will get the number of neutrons: 41 - 20= 21. The atoms has 21 neutrons.

•The number of electrons found in an atom is equal to the number of protons. The atoms has 20 protons which means it has 20 electrons.

So, the answer is:

20 protons, 20 electrons, and 21 neutrons

8 0
3 years ago
Need help ASAP DUE IN LIKE 2 minutes!!!!!!! Points are added
I am Lyosha [343]

Proton:

Positive

Found in Nucleus

Mass of 1 AMU

Neutron:

Neutral

Found in Nucleus

Mass of 1 AMU

Electron:

Negative

Found in orbitals

Mass of 0 AMU

Please mark Brainliest if this helped you! :)

7 0
3 years ago
Work is performed on an object by raising it 2 m above the floor. Which of the
devlian [24]

Answer: Id say C

Explanation:

3 0
3 years ago
Read 2 more answers
The density of NO2 in a 4.50 L tank at 760.0 torr and 25.0 °C is ________ g/l.
Sonbull [250]

The answer is c-1.68

4 0
2 years ago
The last element in any period always has:
brilliants [131]

Answer: The correct option is The properties of a noble gas.

Explanation: There are 7 periods in the periodic table.

The last element of each period are Helium (He), Neon (Ne), Argon (Ar), Krypton (Kr), Xenon (Xe), Radon (Rn) and Ununoctium (Uuo).

  • The electronic configuration for Helium is 1s^2. For He, The outermost electrons are 2.
  • The electronic configuration for all the other elements is ns^2ns^6 ( where, n = 2, 3, 4, 5, 6 and 7 respectively). For all the other gases, the outermost electrons are 8.

All these elements have stable electronic configuration and are not reactive in nature. Hence, they are considered as noble gases.

Therefore, the last element of each period always have the properties of a noble gas.

4 0
3 years ago
Read 2 more answers
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