Answer:
--
--
--Br--
Explanation:
The steps involved in predicting the structure of the alkyl bromide compound are outlined below.
1) An examination of the product shows that the product could only be formed by a substitution reaction.
2) The structure of the alkyl bromide compound can be then predicted by replacing the methoxide group in the product after the substitution of bromine atom. This is because the methoxide ion acts as a strong nucleophile.
Therefore, by consideration the reaction mechanisms of reactions 1 and 2, it can be predicted that the structure of the alkyl bromide compound is
--
--
--Br--
. A pictorial diagram of the alkyl bromide compound is also attached.
Explanation:
<em>(</em><em>P1V1</em><em>)</em><em>/</em><em>T1</em><em>=</em><em>(</em><em>P2V2</em><em>)</em><em>/</em><em>T2</em>
<em>(</em><em>1</em><em>5</em><em>X</em><em>5</em><em>)</em><em>/</em><em>2</em><em>9</em><em>7</em><em>=</em><em>(</em><em>p2x2</em><em>.</em><em>5</em><em>)</em><em>/</em><em>4</em><em>7</em><em>3</em>
<em>p2</em><em>=</em><em>47.78cmHg</em>
The chemical reaction equation for this is
XeF6 + 3H2 ---> Xe + 6HF
Assuming gas behaves ideally, we use the ideal gas formula to solve for number of moles H2 with T = 318.15K (45C), P = 6.46 atm, V = 0.579L. Then we use the gas constant R = 0.08206 L atm K-1 mol-1.
we get n = 0.1433 moles H2
to get the mass of XeF6,
we divide 0.1433 moles H2 by 3 since 1 mole XeF6 needs 3 moles H2 to react then multiply by the molecular weight of XeF6 which is 245.28 g/mole XeF6.
0.1433 moles H2 x

x

= 11.71 g XeF6
Therefore, 11.71 g of XeF6 is needed to completely react with 0.579 L of Hydrogen gas at 45 degrees Celcius and 6.46 atm.
There is one atom in a Monoatomic Ion whereas Many in Polyatomic.
It's simple!!! you're Welcome:)