Answer:
36.28 kg
Explanation:
Given data:
Gravitational potential energy of object = 800 J
Height from ground = 2.245 m
Mass of object = ?
Solution:
Formula:
P.E = mgh
g =acceleration due to gravity = 9.8 m/s²
by putting values,
800 J = m× 9.8 m/s² ×2.25 m
J = kgm²/s²
800 kgm²/s² = m× 22.05 m²/s²
m = 800 kgm²/s² /22.05 m²/s²
m = 36.28 kg
Answer:
THE MOLAR MASS OF THE UNKNOWN MOLECULAR SUBSTANCE IS 200 G/MOL.
Explanation:
Mass of the unknown substance = 0.50 g
Freezing point of the solution = 3.9 °C
Freezing point of pure benzene = 5.5 °C
Freezing point dissociation constant Kf = 5.12°C/m
First, calculate the temperature difference between the freezing point of pure benzene and the final solution freezing point.
Change in temperature = 5.5 -3.9 = 1.6 °C
Next is to calculate the number of moles or molarity of the compound that dissolved.
Using the formula:
Δt = i Kf m
Assume i = 1
So,
1.6 °C = 1 * 5.12 * x/ 0.005 kg of benzene
x = 1.6 * 0.008 / 5.12
x = 0.0128 / 5.12
x = 0.0025 moles.
Next is to calculate the molar mass using the formula, molarity = mass / molar mass
Molar mass = mass / molarity
Molar mass = 0.50 g /0.0025
Molar mass = 200 g/mol
Hence, the molar mass of the unknown compound is 200 g/mol
Answer:
C.KEEPS YOU FROM ILLNESS
Explanation:
THE WORD IMMUNE MEANS TO PROTECT THUS THE IMMUNE SYSTEM IS TO PROTECT YOUR BODY AGAINST PATHOGENS AND DEASISES CAUSING GERMS....
Answer:
single bond= 1 sigma bond
so basically 1
Explanation:
Usually, all bonds between atoms in most organic compounds contain one sigma bond each. If it is a single bond, it contains only sigma bond. Multiple bonds (double and triple), however, contains sigma and pi bonds. Double bonds have one each, and triple bonds have one sigma bond and two pi bonds
The reaction produces 2.93 g H₂.
M_r: 133.34 2.016
2Al + 6HCl → 2AlCl₃ + 3H₂
<em>Moles of AlCl₃</em> = 129 g AlCl₃ × (1 mol AlCl₃/133.34 g AlCl₃) = 0.9675 mol AlCl₃
<em>Moles of H₂</em> = 0.9675 mol AlCl₃ × (3 mol H₂/2 mol AlCl₃) = 1.451 mol H₂
<em>Mass of H₂</em> = 1.451 mol H₂ × (2.016 g H₂/1 mol H₂) = 2.93 g H₂