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3 years ago

What is the simplest form of √324x^6y^8?

Mathematics

1 answer:

omeli [17]3 years ago

4 0

Step-by-step explanation:

$\sqrt{324 {x}^{6} {y}^{8} }$

18x³y⁴

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gizmo_the_mogwai [7]

13 multiplied by 11 is 143

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3 years ago

If the mass of a proton is 2.34 × 10–14 grams, what is the mass of 1,000 protons?

Sergio [31]

The answer is 2.34 x 10-11 g

4 0

3 years ago

What are the roots of the equation x^2+4x-5=f(x)

enyata [817]

Answer:

The roots are -5, 1.

Step-by-step explanation:

$f(x) = x^2 + 4x - 5$

The roots of a function are also the Ox intercepts, so basically we're finding when is the function equal to '0'.

$x^2 + 4x - 5 = 0\\(x-1)(x+5) = 0\\x_1 = 1, x_2 = -5$

3 0

3 years ago

If 2 sides of a triangle are 6 and 16, what is the range of the possible lengths of the third side?

Leno4ka [110]

Answer:

between 10 and 22

Step-by-step explanation:

A side of a triangle must measure between the difference of the lengths of the other two sides and the sum of the lengths of the other two sides.

Difference: 16 - 6 = 10

Sum: 6 + 16 = 22

Answer: between 10 and 22

6 0

3 years ago

Please help FAST I need the answer along with you explaining the steps so I can get it thanks! I’ll give Brainlist also!

kupik [55]

Answer:

The equation of required line is: $\mathbf{5x-8y+34=0}$

Step-by-step explanation:

We need to write equation in the form Ax+By+C=0 of the line parallel to $5x-8y+12=0$ and through the point (-2,3)

First we need to find slope and y-intercept of the required line.

Using equation of line $5x-8y+12=0$ to find slope.

Since the given line and required lines are parallel there slope is same.

Writing equation in slope intercept form: $y=mx+b$ where m is slope.

$5x-8y+12=0 \\-8y=-5x-12\\\frac{-8y}{-8y}=\frac{-5x}{-8}-\frac{12}{-8}\\y=\frac{5}{8}x+\frac{3}{4}$

So, the slope m = 5/8

The slope of required line is $m=\frac{5}{8}$

Now finding y-intercept using slope $m=\frac{5}{8}$ and point(-2,3)

$y=mx+b\\3=\frac{5}{8}(-2)+b\\3=\frac{-5}{4}+b\\b=3+\frac{5}{4}\\b=\frac{3*4+5}{4}\\b=\frac{12+5}{4}\\b=\frac{17}{4}$

So, the equation of required line having slope $m=\frac{5}{8}$ and y-intercept $b=\frac{17}{4}$

$y=mx+b\\y=\frac{5}{8}x+\frac{17}{4}\\y=\frac{5x+17*2}{8}\\y= \frac{5x+34}{8} \\8y=5x+34\\5x-8y+34=0$

So, The equation of required line is: $\mathbf{5x-8y+34=0}$

3 0

2 years ago